CA
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With a CAT percentile of 82 and your CA qualification along with one and a half years of experience, you have good prospects for admission to some of the top MBA colleges in India, including the IIMs, FMS Delhi, XLRI Jamshedpur, and ISB Hyderabad.
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Question : Directions: In each of the following questions, which one set of letters/numbers when sequentially placed at the gaps in the given letter series shall complete it? bb_aab_caab_ca_
Option 1: abac
Option 2: bcab
Option 3: cbba
Option 4: acab
Correct Answer: cbba
Solution : Given: bb_aab_caab_ca_
To fill the series we have to divide the series – bb_aa / b_caa / b_ca_ Let's check each option – First option: abac; bbaaa / bbcaa / bacac (No repeated pattern has been found.) Second option: bcab; bbbaa / bccaa / bacab (No repeated pattern has been found.) Third option: cbba; bbcaa / bbcaa / bbcaa (bbcaa is repeated in the series.) Fourth option: acab; bbaaa / bccaa / bacab (No repeated pattern has been found.)
So, the series becomes bbcaabbcaabbcaa. Hence, the third option is correct.
Question : Directions: Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it? _ cb _ ca _ bacb _ ca _ bac_ d
Option 1: badddb
Option 2: bbbddd
Option 3: addddb
Option 4: addbbb
Correct Answer: addddb
Solution : Given: _ cb _ ca _ bacb _ ca _ bac_ d
To fill the series we have to divide the series→_ cb _ / ca _ b / acb _ / ca _ b / ac_ d Let's check each option – First option: badddb; bcba / cadb / acbd / cadb / acbd (No repeated pattern has been found.) Second option: bbbddd; bcbb / cabb / acbd / cadb / acdd (No repeated pattern has been found.) Third option: addddb; acbd / cadb / acbd / cadb / acbd (acbd and cadb are repeated alternatively.) Fourth option: addbbb; acbd / cadb / acbb / cabb / acbd (No repeated pattern has been found.)
So, the series becomes→acbdcadbacbdcadbacbd. Hence, the third option is correct.
Question : Directions: Which one set of letters/numbers when sequentially placed at the gaps in the given letter series shall complete it? a _ ca _ c _ dc _ d _ ad _
Option 1: ddacdc
Option 2: daadca
Option 3: dadaac
Option 4: ddaacc
Correct Answer: ddaacc
Solution : Given: a _ ca _ c _ dc _ d _ ad _
To fill the series we have to divide the series – a _ c / a _ c / _ dc / _ d _ / ad _ Let's check each option – First option: ddacdc; adc / adc / adc / cdd / adc (No repeated pattern has been found.) Second option: daadca; adc / aac / adc / ddc / ada (No repeated pattern has been found.) Third option: dadaac; adc / aac / ddc / ada / adc (No repeated pattern has been found.) Fourth option: ddaacc; adc / adc / adc / adc / adc (adc is repeated in the series.)
So, the series becomes→adcadcadcadcadc. Hence, the fourth option is correct.
Question : Direction: Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?
a _ ca _ ca _ caa _
Option 1: caca
Option 2: cacc
Option 3: caac
Option 4: ccca
Correct Answer: cacc
Solution : Given:– a _ ca _ ca _ caa _
Let's check the given options –
First option: caca The series becomes accaacaccaaa There is no pattern in the above series.
Second option: cacc The series becomes accaacaccaac The pattern in the series becomes accaac / accaac
Third option: caac The series becomes accaacaacaac There is no pattern in the above series.
Fourth option: ccca The series becomes accaccaccaaa There is no pattern in the above series.
Hence, second option is correct.
Question : Direction: In each of the following question, which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?
a _ b _ ca _ b _ c _ a _ cc
Option 1: a c b c a b
Option 2: a b a b c a
Option 3: a c a c a b
Option 4: a b a b a c
Correct Answer: a c a c a b
Solution : Given -
Let's check the options.
option first: a c b c a b
The series becomes aabccabbccaabcc
There is no pattern in the above series.
option second: a b a b c a
The series becomes aabbcaabbccaacc
option third: a c a c a b
The series becomes aabccaabccaabcc
The pattern in the series becomes aabcc/aabcc/aabcc.
option fourth: a b a b a c
The series becomes aabbcaabbcaaccc
Hence, third option is correct.
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