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Question : If $\operatorname{cosec} A+\cot A=7$, then $\operatorname{cosec} A$ is equal to:

Option 1: $\frac{11}{7}$

Option 2: $\frac{16}{7}$

Option 3: $\frac{25}{7}$

Option 4: $\frac{19}{7}$

Team Careers360 27th Jan, 2024

Correct Answer: $\frac{25}{7}$


Solution : We know if $\operatorname{cosec}x + \cot x = a$, then $\operatorname{cosec} x - \cot x = \frac{1}{a}$
Given, $\operatorname{cosec} A+\cot A=7$ ........(1)
⇒ $\operatorname{cosec} A-\cot A=\frac17$ .........(2)
Solving these equations to get the value of $\operatorname{cosec} A$
(1) + (2), we get,
⇒ $\operatorname{cosec} A+\cot

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I have doubt ( some counselling center said) that other state student cant get mbbs admition in goa

mjaisinghani62 25th Jan, 2024

Hello Sanjay

For admission to mbbs or any other medical courses like bachelor of Physiotherapy, Ayush, Vetrnary, bachelor of homeland medicines surgery,  bachelor of Ayurvedic medicine and surgery seats  are given either through state counseling process or All India quota process.
There are 85 percentage state quota seats and 15

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Question : PQRS is a cyclic quadrilateral. If $\angle$P is three times of $\angle$R and $\angle$S is four times of $\angle$Q, then the sum of $\angle$S + $\angle$R will be:

Option 1: $169^{\circ}$

Option 2: $171^{\circ}$

Option 3: $187^{\circ}$

Option 4: $189^{\circ}$

Team Careers360 25th Jan, 2024

Correct Answer: $189^{\circ}$


Solution : $\angle$P = 3$\angle$R
$\angle$S = 4$\angle$Q
As PQRS is a cyclic quadrilateral,
$\angle$P + $\angle$R = $180^{\circ}$
⇒ 3$\angle$R + $\angle$R = $180^{\circ}$
⇒ 4$\angle$R = $180^{\circ}$
$\therefore$ $\angle$R = $45^{\circ}$
⇒ $\angle$P = 3 × $45^{\circ}$ = $135^{\circ}$
$\angle$S + $\angle$Q = $180^{\circ}$

30 Views

Question : The remainder when $19^{19}+20$ is divided by 18, is:

Option 1: 3

Option 2: 2

Option 3: 1

Option 4: 0

Team Careers360 24th Jan, 2024

Correct Answer: 3


Solution : To find: The remainder when $19^{19}+20$ is divided by 18.
Now, 19 $\equiv$ 1 (mod 18)
⇒ 1919 $\equiv$ 119 (mod 18)
⇒ 1919 $\equiv$ 1 (mod 18)
⇒ (1919 + 20) $\equiv$ (1 + 20) (mod 18)
⇒ (1919

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