Yes, the 47 LPA package might have been either off-campus based placement or through pre-placement offer (PPO) and not the college's on-campus drive. A lot of institutions put off-campus offers in the highest amount  of packages. Always confirm placement reports to be clear.

If you get a government quota seat in a private college through KCET, the tuition fee is subsidized by the Karnataka government. For most professional courses like engineering or medical, the annual tuition fee ranges from sixty-five thousand to ninety-five thousand rupees. For courses like BSc Nursing or allied health sciences, it may range from twenty thousand to forty thousand rupees per year. In addition to the tuition fee, private colleges may charge extra amounts for hostel facilities, which can be around forty thousand to eighty thousand rupees annually, and for lab, library, or development fees, which may be between five thousand to fifteen thousand rupees. University or exam-related fees may also be around three thousand to five thousand rupees.

Hey Divya !

The Master of Prosthetics and Orthotics (MPO) programme at the Indian Spinal Injuries Centre (ISIC), Delhi , for the year 2024, likely commenced in August.

This inference is based on the online registration deadline, which was 20th August 2024 . Typically, academic sessions begin shortly after the closure of admissions.

Hope it helps !

Hello,

The CSAB (Central Seat Allocation Board) counseling application form is used for admission to NITs, IIITs, and GFTIs based on JEE Main ranks. The form is typically available after the conclusion of JoSAA counseling. To apply, visit the official CSAB website, fill out the form with necessary details, upload required documents, and pay the application fee. The process includes special rounds for seat allocation to vacant seats. Stay updated on deadlines via the official website.

Hope this helps you,

Thank you

Correct Answer: INR 12

Solution : Total sum, $P$ = INR 900
The interest rate on the first part, $R_1$ = 4%
The interest rate on the second part, $R_2$ = 2%
Time, $n$ = 1 year
Let $x$ and $900-x$ be the two parts.
Simple interest, SI = $\frac{PnR}{100}$
Simple interest on the first part = simple interest on the second part
⇒ $\frac{x×4×1}{100} = \frac{(900-x)×2×1}{100}$
⇒ $4x = 1800-2x$
⇒ $6x=1800$
⇒ $x=300$
Simple interest in each part
= $\frac{x×4×1}{100}$
= $\frac{300×4×1}{100}$
= INR 12
Hence, the correct answer is INR 12.