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derivativesapplication of derivatives

Prachi Panda 2nd Apr, 2022

Hello,

Application of derivatives are-

  • To calculate the profit and loss in business using graphs.
  • To check the temperature variation.
  • To determine the speed or distance covered such as miles per hour, kilometre per hour etc.
  • Derivatives are used to derive many equations in Physics.
  • The rate of change of a quantity is the most important and general application of derivatives.

Thank you.

69 Views

what is the gas low ? proved th gas low

Prachi Pant 18th Jan, 2021

Hello student,

The gas law is the law that relates the pressure (P), volume (V), and temperature (T) of  a gas. There are three primary gas laws (Charles' Law , Boyle's Law and Avogadro's Law ) of gas that combines into a General Gas equation or Ideal Gas Law.

Formula : PV = nRT

  • P is the pressure of the ideal gas.
  • V is the volume of the ideal gas.
  • n is the amount of ideal gas measured in terms of moles.
  • R is the universal gas constant .
  • T is the temperature.

Proof :

Let us consider the pressure exerted by the gas to be ‘ p,

The volume of the gas be – ‘ v

Temperature be – T

n – be the number of moles of gas

Universal gas constant – R

According to Boyle’s Law ,

At constant n & T, the volume bears an inverse relation with the pressure exerted by a gas.

i.e. v∝1p ………………………………(i)

According to Charles’ Law,

When p & n are constant, the volume of a gas bears a direct relation with the Temperature.

i.e. v∝T ………………………………(ii)

According to Avogadro’s Law,

When p & T are constant, then the volume of a gas bears a direct relation with the number of moles of gas.

i.e. v∝n ………………………………(iii)

Combining all the three equations, we have-

v∝nTp

or pv=nRT

where R is the Universal gas constant , which has a value of 8.314 J/mol-K

All the best and thank you.


1522 Views

find first derivative of y=x.tan^-1.x

ARYAN SAGAR 5th Jan, 2021
Dear student,

Our given equation is y = xtan^-1x

So we have to find first derivative or dy/dx.

Now, two functions are multiplied to each other so we will use the product rule of differentiation.

So, dy/ dx = x (1/1+x^2) + tan^-1x (1)

So, our answer is :-

dy/dx = tan^-1x + x/(1+x^2).

202 Views

differentiate from definition (1)- power of e is 3x

Manidipa Kundu Student Expert 10th May, 2020

hi,

you may use the differentiate formula,

dy/dx

suppose here y=e^3x,

formula for d[e^x]/dx is, e^x, now take the whole 3x as x , by using this formula you will get e^3x, here 3x is also a function of x, so we need to again differentiate it  with respect to x, the final result will be 3* e^3x.



90 Views

2nd order derivative of x square+6xy+y square

Smrity 5th Mar, 2020

Hello,

The given equation,

x^2+6xy+y^2

Differentiating the above equation

d/dx(x^2+6xy+y^2)=2x+6y

differentiating the above solution to get the second order derivative we get,

d/dx(2x+6y)=2

therefore, the second order derivative of the above equation that is, x^2+6xy+y^2 is 2.

Hope this helps.

All the best!

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