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derivativesapplication of derivatives

Prachi Panda 2nd Apr, 2022

Hello,

Application of derivatives are-

  • To calculate the profit and loss in business using graphs.
  • To check the temperature variation.
  • To determine the speed or distance covered such as miles per hour, kilometre per hour etc.
  • Derivatives are used to derive many equations in Physics.
  • The rate of change of a quantity is the most important and general application of derivatives.

Thank you.

69 Views

what is the gas low ? proved th gas low

Prachi Pant 18th Jan, 2021

Hello student,

The gas law is the law that relates the pressure (P), volume (V), and temperature (T) of  a gas. There are three primary gas laws (Charles' Law , Boyle's Law and Avogadro's Law ) of gas that combines into a General Gas equation or Ideal Gas Law.

Formula : PV = nRT

  • P is the pressure of the ideal gas.
  • V is the volume of the ideal gas.
  • n is the amount of ideal gas measured in terms of moles.
  • R is the universal gas constant .
  • T is the temperature.

Proof :

Let us consider the pressure exerted by the gas to be ‘ p,

The volume of the gas be – ‘ v

Temperature be – T

n – be the number of moles of gas

Universal gas constant – R

According to Boyle’s Law ,

At constant n & T, the volume bears an inverse relation with the pressure exerted by a gas.

i.e. v∝1p ………………………………(i)

According to Charles’ Law,

When p & n are constant, the volume of a gas bears a direct relation with the Temperature.

i.e. v∝T ………………………………(ii)

According to Avogadro’s Law,

When p & T are constant, then the volume of a gas bears a direct relation with the number of moles of gas.

i.e. v∝n ………………………………(iii)

Combining all the three equations, we have-

v∝nTp

or pv=nRT

where R is the Universal gas constant , which has a value of 8.314 J/mol-K

All the best and thank you.


1522 Views

find first derivative of y=x.tan^-1.x

ARYAN SAGAR 5th Jan, 2021
Dear student,

Our given equation is y = xtan^-1x

So we have to find first derivative or dy/dx.

Now, two functions are multiplied to each other so we will use the product rule of differentiation.

So, dy/ dx = x (1/1+x^2) + tan^-1x (1)

So, our answer is :-

dy/dx = tan^-1x + x/(1+x^2).

202 Views

differentiate from definition (1)- power of e is 3x

Manidipa Kundu Student Expert 10th May, 2020

hi,

you may use the differentiate formula,

dy/dx

suppose here y=e^3x,

formula for d[e^x]/dx is, e^x, now take the whole 3x as x , by using this formula you will get e^3x, here 3x is also a function of x, so we need to again differentiate it  with respect to x, the final result will be 3* e^3x.



90 Views

2nd order derivative of x square+6xy+y square

Smrity 5th Mar, 2020

Hello,

The given equation,

x^2+6xy+y^2

Differentiating the above equation

d/dx(x^2+6xy+y^2)=2x+6y

differentiating the above solution to get the second order derivative we get,

d/dx(2x+6y)=2

therefore, the second order derivative of the above equation that is, x^2+6xy+y^2 is 2.

Hope this helps.

All the best!

919 Views

I have completed basic registration.I couldnt generate RUC code. How can I generate RUC.

Anmol Vig 23rd Feb, 2019

Hi Aspirant! The authorities have provided an opportunity to the applicants to generate the code for AIIMS MBBS final registration 2019. Candidates who have not generated the link can do so and fill the final registration form from February 23 until March 12.

As per the recent notification, aspirants who have completed the basic registration of AIIMS MBBS 2019 application form but has not generated Registration Unique Code (RUC) can get it from February 23 to March 12.

For the final registration and code generation, kindly visit the below mentioned link :

https://medicine.careers360.com/articles/aiims-mbbs-application-form

I hope this information has helped you! 

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