Hello Student ,

As NTA already announced the result for session 1 so you can surely check your percentile at the offical NTA webiste considering you as a general category candidate your chances would be tough enough to get admission into NITs and IIITs but no worry you still have another chance to score better in the session 2 which is in April . Meanwhile you you want to check your admission chances you can refer to Careers360 free college predictor or rank predictor tool.

The link for the college predictor or rank predictor tool is given below-
https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna
https://engineering.careers360.com/jee-main-rank-predictor?utm_source=qna

Hello student,

Based on your percentile, it will be difficult to get colleges like NITs and IIITs or any college through JoSAA Counselling for that matte. I suggest that you appear for the second attempt to improve your score and get chances of admission into better colleges.

If you want to check your rank range based on your percentile, then you can refer to the Careers360 JEE Main Rank Predictor: https://engineering.careers360.com/jee-main-rank-predictor?

If you need more information regarding which colleges you would be eligible for based on your marks and details, then you can refer to the Careers360 JEE Main College Predictor: https://engineering.careers360.com/jee-main-college-predictor?

Yes all the institutes you mentioned offer animation and game design course. IIT Bombay offers Animation design as full time 2 years course.

Eligibility criteria is Bachelors Degree in Design/Engineering/Architecture/Interior design: 10+2+4 and also offers a four year professional program BFA with entry after 10+2.

VEL TECH offers a professional four year Gaming and Animation undergraduate course.

Vellore Institute of Technology (VIT), Bhopal offers a professional four year Gaming technology under B.Tech computer science engineering.

Many colleges in bangalore such as Jain university, Alliance university also offer Gaming and Animation courses.

Refer the below links for further information.

https://vit.ac.in/files/VITEEE-2024-information-brochure.pdf

https://www.careers360.com/colleges/industrial-design-centre-indian-institute-of-technology-mumbai/mdes-animation-design-course

https://www.veltech.edu.in/admission/

Hello,

Scoring 200 plus in JEE Advanced puts you in a very competitive position within the SC category, but admission to CSE at top IITs depends on your rank. Aim for the highest possible rank for better chances. But yes you have a great chance of getting.

Hope this helps you,

Thank you

Correct Answer: 40 cm

Solution :
The perpendicular from the centre of a circle to a chord bisects the chord.
By Pythagoras theorem:
Hypotenuse² = Base² + Perpendicular²
MP = PN = $\frac{\text{MN}}{2}$ = $\frac{48}{2}$ = 24 cm
Distance from the centre as $d_{1}$ = 15 cm
From the Pythagorean theorem, the radius $r$ of the circle is:
$r = \sqrt{a^{2}+d_{1}^{2}}$
⇒ $r = \sqrt{24^{2}+7^{2}}$
⇒ $r = \sqrt{576+49}$
⇒ $r = \sqrt{625}$
⇒ $r= 25$ cm
For the unknown chord, let's denote half of its length as $b$ and the known distance from the centre as $d_{2}$ = 15 cm
Again using the Pythagorean theorem, we find $\frac{x}{2}$ as
$\frac{x}{2} = \sqrt{r^{2}-d_{2}^2}$
⇒ $\frac{x}{2} = \sqrt{25^{2}-15^2}$
⇒ $\frac{x}{2} = \sqrt{400}$
⇒ $\frac{x}{2} = 20$ cm
So, the full length of the unknown chord is $x$ = 2 × 20 cm = 40 cm
Hence, the correct answer is 40 cm.

Correct Answer: Rs. 17,298

Solution : Marked price = Rs. 20,000
Successive discounts are 7% and 7%.
Selling price = $(100-D_1)\% \text{ of } (100-D_2)\% \text{ of } \text{MP}$, where D₁ and D₂ are discount percentage and MP is the marked price.
So, the selling price = 93% of 93% of Rs. 20,000 = $\frac{93 × 93 × 20000}{100 × 100}$
= 93 × 93 × 2
= Rs. 17,298
Hence, the correct answer is Rs. 17,298.