Hello,

Based on your son's percentile and category, it would be difficult to get admission into NITs and IIITs.

However, he could get admission into some GFTIs, like Birla Institute of Technology (both Ranchi and Mesra), Indian Institute of Carpet Technology, Bhadohi, National Institute of Food Technology, Entrepreneurship and Management, Thanjavur, etc.

If you want to check more govt. colleges and GFTIs that the student is take admission into based on JoAAA counselling or other state and university level counselling, then you can take help form the Careers360 JEE college predictor: https://engineering.careers360.com/jee-main-college-predictor?

As you are from OC General category, you could get admission in the following IIITs.

1. IIIT Allahabad
2. IIITDM, Jabalpur
3. IIIT, Gwalior
4. IIIT, Tiruchirappalli
5. IIITDM, Kurnool.

You could get into GFITs also with the marks you scored. The eligible colleges are as follows

If you wanna pursue engineering,  then

1. Institute of Infrastructure, Technology, Research and Management,  Ahmedabad
2. Institute of Technology, Guru Ghasidas Vishwavidyalaya, Bilaspur
3. J.K. Institute of Applied Physics & Technology, Allahabad
4. National Institute of Electronics and Information Technology, Maharashtra
5. Assam University, Silchar

If you want to pursue architecture and planning, then you can apply for the below colleges.

1. School of Planning & Architecture, New Delhi
2. School of Planning & Architecture, Bhopal
3. School of Planning & Architecture, Vijayawada

According to your percentile your all India rank will be around 87219. And as per the last year's cutoff you may have a tough chance to get a seat in NITs and IIITs for CS branch.

But you might be having some chances in GFTIs for the branch of CS.

To know more about the chances you can use our college predictor tool: https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna

While diploma holders cannot directly enter NITs or IIITs through JEE Mains in the first year, there are options! Some institutes offer lateral entry to the second year based on separate exams, and diploma holders can also apply as fresh candidates with their JEE Mains score. Additionally, many other engineering colleges accept diploma holders through various avenues. Explore these options and check individual institute websites for specific details and procedures.

MHT CET is open to non-Maharashtrian students, but the chances of getting into top colleges can be more competitive due to limited seats for out-of-state students. You can still get into good colleges, but you might need to score higher in the exam, especially for popular courses and institutions. Additionally, the fee structure for non-Maharashtrian students can be higher. To maximize your chances, aim for a strong score and review the specific eligibility criteria for each college.

Correct Answer: 146

Solution : Given:

In the first column, (7)² + (5)² + (3)² = 49 + 25 + 9 = 83

In the second column, (6)² + (4)² + (2)² = 36 + 16 + 4 = 56

In the third column, (8)² + (9)² + (1)² = 64 + 81 + 1 = 146

So, the missing number is 146.

Hence, first option is correct.

Correct Answer: 18 + 6 – 4 × 2 ÷ 3 = 26

Solution : Given:

'+' means '×'

'–' means '÷'

'×' means '+'

'÷' means '–'

Option first:    18 – 6 × 7 ÷ 2 + 8 = 63

Now, replacing the symbols as per the code language given in the question, we get –

18 – 6 × 7 ÷ 2 + 8

Solving this equation using the BODMAS rule, we get –

= 18 – 6 × 3.5 + 8

= 18 – 21 + 8

= 5 is not equal to 63

Option second:    18 ÷ 6 + 4 – 2 ÷ 3 = 22

Now, replacing the symbols as per the code language given in the question, we get –

18 – 6 × 4 ÷ 2 – 3

Solving this equation using the BODMAS rule, we get –

= 18 – 6 × 2 – 3

= 18 – 12 – 3

= 3 is not equal to 22

Option third:    18 + 6 – 4 × 2 ÷ 3 = 26

Now, replacing the symbols as per the code language given in the question, we get –

18 × 6 ÷ 4 + 2 – 3

Solving this equation using the BODMAS rule, we get –

= 18 × 1.5 + 2 – 3

= 27 + 2 – 3

= 26

Option fourth:    18 × 6 – 4 + 7 × 8 = 47

Now, replacing the symbols as per the code language given in the question, we get –

18 + 6 ÷ 4 × 7 + 8

Solving this equation using the BODMAS rule, we get –

= 18 + 1.5 × 7 + 8

= 18 + 10.5 + 8

= 36.5 is not equal to 47

Hence, option third is correct.

Hi

hope you doing well

You can opt to reappear for your board exams to improve your percentage. This is the most straightforward way to ensure you meet the 75% criteria. but it will take more time.

second option is that, If you're considering switching to the NIOS board, this is a viable option. NIOS is a recognized board that allows you to take examinations in a flexible manner. By completing your secondary education through NIOS, you can aim to score 75% or more, which will help fulfill the eligibility requirements for JEE Main and subsequent admissions.

According to the JEE guidelines, you must score at least 75% in your Class 12 (or equivalent) exams or be in the top 20 percentile of your respective board. If you take the NIOS route, ensure that your score meets this requirement.

there is major chance of that you won't able to give jee exam that year so prepare for jee mains exam next year you will have limited attempt.

hope you get it and find it useful

Best Wishes.

Hello,

Youh can have a chance of getting around 45000-5000 obc rank. This is totally based on previous year trends and is subject to change with time.  Looking at the trends we can say that you don not have a good chance of getting NITs/ IIITs, you have a small chance of getting NIT Agartala, NIT Sikkim.

Hope this helps you,

Thank you

https://engineering.careers360.com/articles/list-of-indian-institutes-of-information-technology-iiits