JAC
As a Tamil Nadu student who completed 8 years of education in Karnataka, you are considered a Karnataka student for the purpose of the Karnataka Post Graduate Common Entrance Test (PGCET). This classification is based on the Karnataka Examination Authority's (KEA) guidelines, which state that candidates who have studied in
For Class 11 students, several scholarship exams are available to help with education costs. Popular ones include:
1. Kishore Vaigyanik Protsahan Yojana (KVPY) – for science students.
2. National Talent Search Examination (NTSE) – for overall academic excellence.
3. Olympiads – like Science, Maths, and English Olympiads.
4. State Government
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For admission to Netaji Subhas University of Technology (NSUT) , a domicile certificate is required for candidates seeking seats under the Delhi quota. As an OBC candidate from Delhi, you will need to provide a valid domicile certificate to be eligible for the OBC category
Dear aspirant !
Hope you are doing well ! Don't worry when the counselling will start we will help you in getting better college at any cost . Joint Admission Committee (JAC) for counselling and admission to Undergraduate Programmes in premier Delhi Government funded universities, offering Engineering, Architecture and Management
Question : Directions: Select the option in which the numbers share the same relationship in the set as that shared by the numbers in the given set. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g.13 – operations on 13 such as adding/subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed) (32, 24, 8) (48, 42, 6)
Option 1: (64, 62, 8)
Option 2: (56, 50, 6)
Option 3: (16, 14, 4)
Option 4: (18, 12, 4)
Correct Answer: (56, 50, 6)
Solution : Given: (32, 24, 8); (48, 42, 6) The pattern is – (32, 24, 8)→32 – 24 = 8 (48, 42, 6)→48 – 42 = 6
Let's check each option – First option: (64, 62, 8) = 64 – 62 = 2 ≠ 8
Question : The perimeter of two similar triangles $\Delta \mathrm{ABC}$ and $\Delta\mathrm{ PQR}$ are $60\;\mathrm{cm}$ and $36\;\mathrm{cm}$ respectively. If $\mathrm{PQ} = 18\;\mathrm{ cm}$, then $\mathrm{AB}$ is:
Option 1: $20\;\mathrm{cm}$
Option 2: $24\;\mathrm{cm}$
Option 3: $36\;\mathrm{cm}$
Option 4: $30\;\mathrm{cm}$
Correct Answer: $30\;\mathrm{cm}$
Solution : Given: The perimeter of two similar triangles $\Delta \mathrm{ABC}$ and $\Delta\mathrm{ PQR}$ are $60\;\mathrm{cm}$ and $36\;\mathrm{cm}$ respectively. The length of $\mathrm{PQ} = 18\;\mathrm{ cm}$. Since the ratio of the corresponding sides of similar triangles is the same as the ratio of their perimeters. $⇒\frac{\mathrm{AB}}{\mathrm{PQ}} =
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