Maharashtra AAC Common Entrance Test
Question : The value of $\frac{3\left(\operatorname{cosec}^2 26^{\circ}-\tan ^2 64^{\circ}\right)+\left(\cot ^2 42^{\circ}-\sec ^2 48^{\circ}\right)}{\cot \left(22^{\circ}-\theta\right)-\operatorname{cosec}^2\left(62^{\circ}+\theta\right)-\tan \left(\theta+68^{\circ}\right)+\tan ^2\left(28^{\circ}-\theta\right)}$ is:
Option 1: 3
Option 2: 4
Option 3: –1
Option 4: –2
Correct Answer: –2
Solution : $\frac{3\left(\operatorname{cosec}^2 26^{\circ}-\tan ^2 64^{\circ}\right)+\left(\cot ^2 42^{\circ}-\sec ^2 48^{\circ}\right)}{\cot \left(22^{\circ}-\theta\right)-\operatorname{cosec}^2\left(62^{\circ}+\theta\right)-\tan \left(\theta+68^{\circ}\right)+\tan ^2\left(28^{\circ}-\theta\right)}$ $= \frac{3\left(\operatorname{sec}^2 64^{\circ}-\tan ^2 64^{\circ}\right)+\left(\cot ^2 42^{\circ}-\operatorname{cosec} ^2 42^{\circ}\right)}{\tan \left(68^{\circ}+\theta\right)-\operatorname{cosec}^2\left(62^{\circ}+\theta\right)-\tan \left(\theta+68^{\circ}\right)+\cot ^2\left(62^{\circ}+\theta\right)}$ $= \frac{3\left(1\right)+\left(\cot ^2 42^{\circ}-1-\cot ^2 42^{\circ}\right)}{-(\operatorname{cosec}^2\left(62^{\circ}+\theta\right)-\cot ^2\left(62^{\circ}+\theta\right))}$ $= \frac{3-1}{-1}$ $= -2$ Hence, the correct answer is –2.
Question : Directions: Select the letter-cluster from among the given options that can replace the question mark (?) in the following series. AEI, EIO, IOU, ?
Option 1: UAE
Option 2: AEI
Option 3: OUA
Option 4: All
Correct Answer: OUA
Solution : Given: AEI, EIO, IOU, ?
Vowels are replaced with immediate next vowels according to the English alphabetical series and the order is – A, E, I, O, U AEI → The immediate next vowel of A is E, the Immediate next vowel of E is I, and the immediate next vowel of I is O → EIO EIO → The immediate next vowel of E is I, the Immediate next vowel of I is O, and the immediate next vowel of O is U → IOU IOU → The immediate next vowel of I is O, the Immediate next vowel of O is U, and the immediate next vowel of U is A → OUA
So, the required missing term in the series is OUA. Hence, the third option is correct.
Question : Case Study 72
OPQ Corporation is a conglomerate planning to trade its shares on a stock exchange. The company's management is reviewing the roles of stockbrokers.
Question :
What type of broker offers advice to clients and executes orders on their behalf?
Option 1: Full-service broker
Option 2: Discount broker
Option 3: Floor broker
Option 4: Specialist broker
Correct Answer: Full-service broker
Solution : The correct answer is (a) Full-service broker
A full-service broker is a type of broker that offers a wide range of services to clients, including investment advice, research, financial planning, and execution of orders on behalf of their clients. They provide personalized assistance and guidance to help clients make informed investment decisions. In addition to executing trades, they often offer comprehensive financial services, portfolio management, and recommendations based on their expertise and analysis of the market. Clients typically pay higher fees or commissions for the additional services and advice provided by full-service brokers.
Question : Three metallic spheres of radii 10 cm, 8 cm, and 6 cm, respectively are melted to form a single solid cone of radius 12 cm. Find the curved surface area of the cone, correct to two places of decimal. (Take $\pi=3.14$)
Option 1: $1664.50 \text{ cm}^2$
Option 2: $1669.86 \text{ cm}^2$
Option 3: $1876.79 \text{ cm}^2$
Option 4: $1864.41 \text{ cm}^2$
Correct Answer: $1864.41 \text{ cm}^2$
Solution : The volume of a sphere, where $r$ is the radius. $V = \frac{4}{3}\pi r^3$ The volume of a cone, where $r$ is the radius and $h$ is the height. $V = \frac{1}{3}\pi r^2 h$ The volume of the three spheres is equal to the volume of the cone since the spheres are melted to form the cone. $⇒\frac{4}{3}\pi (10^3 + 8^3 + 6^3) = \frac{1}{3}\pi r^2 h$ $⇒\frac{4}{3}\pi (10^3 + 8^3 + 6^3) = \frac{1}{3}\pi (12)^2 h$ $⇒ 4(10^3 + 8^3 + 6^3) = (12)^2 h$ $⇒ 6912= 144 h$ $⇒h = 48 \text{ cm}$ Now, the slant height, $l = \sqrt{r^2 + h^2}= \sqrt{(12)^2 + (48)^2} = 49.477 \text{ cm}$ The curved surface area of a cone, where $l$ is the slant height of the cone. $= \pi r l= \pi ×(12)× (49.477)=1864.41 \text{ cm}^2$ Hence, the correct answer is $1864.41 \text{ cm}^2$.
Question : Direction: Some equation have been solved on the basis of certain system. Find out the correct answer for the unsolved equation on that basis.
9 x 7 x 4 = 794
3 x 4 x 6 = 436
4 x 2 x 7 = ?
Option 1: 742
Option 2: 247
Option 3: 724
Option 4: 472
Correct Answer: 247
Solution : Here, the given equations follows a pattern in which the first number and the middle number in LHS becomes the tens place digit and the hundreds place digit in the answer part in RHS respectively.
⇒ 9 x 7 x 4 = 794
⇒ 3 x 4 x 6 = 436
Following the same pattern in the unsolved equation, we get –
⇒ 4 x 2 x 7 = 247
Hence, option second is correct.
Question : Who among the following Mauryan kings turned to Buddhism and its tenet of nonviolence after the Kalinga war?
Option 1: Chandragupta Maurya
Option 2: Bindusara
Option 3: Ashoka
Option 4: Dasharatha
Correct Answer: Ashoka
Solution : The correct answer is Ashoka.
The last significant ruler of India's Mauryan dynasty was Ashoka. Following his victorious conquest of the Kalinga, he turned to Buddhism, gave up violent conquest and embraced a strategy he called "conquer by dharma," realising the carnage of the conflict.
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