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Maharashtra AAC Common Entrance Test

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Question : The value of $\frac{3\left(\operatorname{cosec}^2 26^{\circ}-\tan ^2 64^{\circ}\right)+\left(\cot ^2 42^{\circ}-\sec ^2 48^{\circ}\right)}{\cot \left(22^{\circ}-\theta\right)-\operatorname{cosec}^2\left(62^{\circ}+\theta\right)-\tan \left(\theta+68^{\circ}\right)+\tan ^2\left(28^{\circ}-\theta\right)}$ is:

Option 1: 3

Option 2: 4

Option 3: –1

Option 4: –2

Team Careers360 23rd Jan, 2024

Correct Answer: –2


Solution : $\frac{3\left(\operatorname{cosec}^2 26^{\circ}-\tan ^2 64^{\circ}\right)+\left(\cot ^2 42^{\circ}-\sec ^2 48^{\circ}\right)}{\cot \left(22^{\circ}-\theta\right)-\operatorname{cosec}^2\left(62^{\circ}+\theta\right)-\tan \left(\theta+68^{\circ}\right)+\tan ^2\left(28^{\circ}-\theta\right)}$
$= \frac{3\left(\operatorname{sec}^2 64^{\circ}-\tan ^2 64^{\circ}\right)+\left(\cot ^2 42^{\circ}-\operatorname{cosec} ^2 42^{\circ}\right)}{\tan \left(68^{\circ}+\theta\right)-\operatorname{cosec}^2\left(62^{\circ}+\theta\right)-\tan \left(\theta+68^{\circ}\right)+\cot ^2\left(62^{\circ}+\theta\right)}$
$= \frac{3\left(1\right)+\left(\cot ^2 42^{\circ}-1-\cot ^2 42^{\circ}\right)}{-(\operatorname{cosec}^2\left(62^{\circ}+\theta\right)-\cot ^2\left(62^{\circ}+\theta\right))}$
$= \frac{3-1}{-1}$
$= -2$
Hence, the correct answer is –2.

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Question : Directions: Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.
AEI, EIO, IOU, ?

Option 1: UAE

Option 2: AEI

Option 3: OUA

Option 4: All

Team Careers360 25th Jan, 2024

Correct Answer: OUA


Solution : Given:
AEI, EIO, IOU, ?

Vowels are replaced with immediate next vowels according to the English alphabetical series and the order is –
A, E, I, O, U
AEI → The immediate next vowel of A is E, the Immediate next vowel of E is I, and the immediate next vowel of I is O → EIO
EIO → The immediate next vowel of E is I, the Immediate next vowel of I is O, and the immediate next vowel of O is U → IOU
IOU → The immediate next vowel of I is O, the Immediate next vowel of O is U, and the immediate next vowel of U is A → OUA

So, the required missing term in the series is OUA. Hence, the third option is correct.

8 Views

Question : Case Study 72

OPQ Corporation is a conglomerate planning to trade its shares on a stock exchange. The company's management is reviewing the roles of stockbrokers.

Question : 

What type of broker offers advice to clients and executes orders on their behalf?

Option 1: Full-service broker
 

Option 2: Discount broker
 

Option 3: Floor broker

 

Option 4: Specialist broker

Team Careers360 25th Jan, 2024

Correct Answer: Full-service broker
 


Solution : The correct answer is (a) Full-service broker

A full-service broker is a type of broker that offers a wide range of services to clients, including investment advice, research, financial planning, and execution of orders on behalf of their clients. They provide personalized assistance and guidance to help clients make informed investment decisions. In addition to executing trades, they often offer comprehensive financial services, portfolio management, and recommendations based on their expertise and analysis of the market. Clients typically pay higher fees or commissions for the additional services and advice provided by full-service brokers.

8 Views

Question : Three metallic spheres of radii 10 cm, 8 cm, and 6 cm, respectively are melted to form a single solid cone of radius 12 cm. Find the curved surface area of the cone, correct to two places of decimal. (Take $\pi=3.14$)

Option 1: $1664.50 \text{ cm}^2$

Option 2: $1669.86 \text{ cm}^2$

Option 3: $1876.79 \text{ cm}^2$

Option 4: $1864.41 \text{ cm}^2$

Team Careers360 19th Jan, 2024

Correct Answer: $1864.41 \text{ cm}^2$


Solution : The volume of a sphere, where $r$ is the radius.
$V = \frac{4}{3}\pi r^3$
The volume of a cone, where $r$ is the radius and $h$ is the height.
$V = \frac{1}{3}\pi r^2 h$
The volume of the three spheres is equal to the volume of the cone since the spheres are melted to form the cone. 
$⇒\frac{4}{3}\pi (10^3 + 8^3 + 6^3) = \frac{1}{3}\pi r^2 h$
$⇒\frac{4}{3}\pi (10^3 + 8^3 + 6^3) = \frac{1}{3}\pi (12)^2 h$
$⇒ 4(10^3 + 8^3 + 6^3) = (12)^2 h$
$⇒ 6912= 144 h$
$⇒h = 48 \text{ cm}$
Now, the slant height, $l = \sqrt{r^2 + h^2}= \sqrt{(12)^2 + (48)^2} = 49.477 \text{ cm}$
The curved surface area of a cone, where $l$ is the slant height of the cone. 
$= \pi r l= \pi ×(12)× (49.477)=1864.41 \text{ cm}^2$
Hence, the correct answer is $1864.41 \text{ cm}^2$.

16 Views

Question : Direction: Some equation have been solved on the basis of certain system.
Find out the correct answer for the unsolved equation on that basis.

9 x 7 x 4 = 794 

3 x 4 x 6 = 436 

4 x 2 x  7 = ?

Option 1: 742

Option 2: 247

Option 3: 724

Option 4: 472

Team Careers360 22nd Jan, 2024

Correct Answer: 247


Solution : Here, the given equations follows a pattern in which the first number and the middle number in LHS becomes the tens place digit and the hundreds place digit in the answer part in RHS respectively.

⇒ 9 x 7 x 4 = 794 

⇒ 3 x 4 x 6 = 436 

Following the same pattern in the unsolved equation, we get –

⇒ 4 x 2 x  7 = 247

Hence, option second is correct.

8 Views

Question : Who among the following Mauryan kings turned to Buddhism and its tenet of nonviolence after the Kalinga war?

Option 1: Chandragupta Maurya

Option 2: Bindusara

Option 3: Ashoka

Option 4: Dasharatha

Team Careers360 25th Jan, 2024

Correct Answer: Ashoka


Solution : The correct answer is Ashoka.

The last significant ruler of India's Mauryan dynasty was Ashoka. Following his victorious conquest of the Kalinga, he turned to Buddhism, gave up violent conquest and embraced a strategy he called "conquer by dharma," realising the carnage of the conflict.

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