Manipal University, Jaipur
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Established in 2011, Manipal University Jaipur, a part of the Manipal Education and Medical Group, provides a range of academic courses in engineering, management, social sciences, business and commerce, journalism and mass communication, law, and hotel management. The university also offers UGC-approved online degree programs at both bachelor's and master's levels, enabling students to acquire a comprehensive education and enhance their skills for successful careers in various fields. Online Manipal University has garnered approvals and accreditation from key national authorizing bodies, including the University Grants Commission (UGC), All India Council of Technical Education (AICTE), and World Education Services (WES).
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Manipal University conducts the Manipal Entrance Test (MET) to select eligible candidates for its undergraduate and postgraduate courses. The university also considers scores from various national-level entrance exams for admission. To be eligible for enrollment, candidates must have a minimum aggregate of 50% in Class 12. Additionally, the duration of a full-time BTech degree is four years, while a BTech Lateral Entry program is three years.
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Question : ______ is the change in total utility due to the consumption of one additional unit of a commodity.
Option 1: Product Utility (PU)
Option 2: Revenue Utility (RU)
Option 3: Demand Utility (DU)
Option 4: Marginal Utility (MU)
Correct Answer: Marginal Utility (MU)
Solution : The correct option is Marginal Utility (MU).
The change in total utility due to the consumption of one additional unit of a commodity is called Marginal Utility. It is the additional satisfaction or benefit that a consumer derives from consuming one more unit of a good or service. Marginal Utility is a key concept in microeconomics.
Question : Pipes A and B can fill a tank in 12 minutes and 15 minutes, respectively. The tank when full can be emptied by pipe C in $x$ minutes. When all three pipes are opened simultaneously, the tank is full in 10 minutes. The value of $x$ is:
Option 1: 18
Option 2: 15
Option 3: 20
Option 4: 24
Correct Answer: 20
Solution : Pipe A can do 1 unit work = $\frac{1}{12}$ minutes Pipe B can do 1 unit work = $\frac{1}{15}$ minutes Pipe C can do 1 unit work = $-\frac{1}{x}$ minutes Together they can fill the tank = $\frac{1}{10}$ minutes Total work = Efficiency × days $⇒\frac{1}{\text{total days}} = \frac{1}{\text{A}} + \frac{1}{\text{B}} - \frac{1}{\text{C}}$ $⇒\frac{1}{10} = \frac{1}{12} + \frac{1}{15} - \frac{1}{x}$ $⇒\frac{1}{x} = \frac{1}{12} + \frac{1}{15} - \frac{1}{10}$ $⇒\frac{1}{x} = \frac{(5 + 4 - 6)}{60}$ $⇒\frac{1}{x} = \frac{3}{60}$ $\therefore x = 20$ Hence, the correct answer is 20.
Question : Directions: Which term from among the given options can replace the question mark (?) in the following series to make it logically complete? LT 48, ?, NV 42, OW 39, PX 36
Option 1: MU 45
Option 2: NU 44
Option 3: NS 44
Option 4: MS 46
Correct Answer: MU 45
Solution : Given: LT 48, ?, NV 42, OW 39, PX 36
In the above-given series, add 1 to the place values of the first and the second letters and subtract 3 from the number, to obtain the next term. LT 48→L + 1 = M; T + 1 = U; 48 – 3 = 45→MU 45 MU 45→M + 1 = N; U + 1 = V; 45 – 3 = 42→NV 42 NV 42→N + 1 = O; V + 1 = W; 42 – 3 = 39→OW 39 OW 39→O + 1 = P; W + 1 = X; 39 – 3 = 36→PX 36
So, MU 45 is the required term of the given series. Hence, the first option is correct.
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