Staff Selection Commission Sub Inspector Exam
Question : Select the most appropriate option that can substitute the underlined segment in the given sentence. If there is no need to substitute it, select ‘No substitution required’. Sia is always afraid of loosing her favourite doll.
Option 1: of losing
Option 2: to loosing
Option 3: No substitution required
Option 4: for loosing
Correct Answer: of losing
Solution : The correct option is the first option.
Explanation: Losing is the correct spelling here. It means failing to retain something, which fits the context of Sia being afraid of losing her favourite doll.
Therefore, the correct sentence would be, "Sia is always afraid of losing her favourite doll."
Question : Directions: Two positions of a cube are given. Based on them find out which number is found opposite number 1 in the given cube.
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 3
Solution : According to the dice rule, if two positions of the same dice are given with two common faces but in different orientations then out of those two common faces the faces that are not common are opposite to each other.
Therefore, the opposite face of the 1 is 3. Hence, the third option is correct.
Question : Directions: A cube is made by folding the given sheet. In the cube so formed, what would be the symbol on the opposite side of ?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : In the 3D view of dice, 1. Each face out of the three faces in the 3D view should be from all the pairs. 2. Two opposite faces cannot appear adjacently in the 3D view of a folded cube figure. So, the opposite pairs of faces are as follows –
So, in the 3D view of dice, the face opposite the face showing is . Hence, the first option is correct.
Question : In an equilateral $\triangle$ PQR, S is the point on the side QR such that QR = 3QS. If PQ = 9 cm, then what will be the length (in cm) of PS?
Option 1: $\sqrt{60} $
Option 2: $\sqrt{63}$
Option 3: $\sqrt{62}$
Option 4: $\sqrt{61}$
Correct Answer: $\sqrt{63}$
Solution : Draw PT perpendicular to QR. PT = $\frac{\sqrt3}{2}\times 9=\frac{9\sqrt3}{2}$ cm QT = $\frac{9}{2}$ cm Given, QR = 3QS ⇒ QS = $\frac{9}{3}$ = 3 cm ST = QT – QS =$\frac{9}{2} -3$ = $\frac{3}{2}$ Using Pythagoras' theorem: Hypotenuse2 = Base2 + Perpendicular2 PS2 = PT2 + ST2 (PS)2 = $(\frac{9\sqrt3}{2})^2 + (\frac{3}{2})^2$ ⇒ $(PS)^2=\frac{243}{4} + \frac{9}{4}$ ⇒ $(PS)^2=\frac{252}{4}$ ⇒ $(PS)^2=63$ ⇒ $PS=\sqrt{63}$ Hence, the correct answer is $\sqrt{63}$ cm.
Question : Directions: In the following question, the given sentence has four parts marked P, Q, R, and S. Choose the part of the sentence with the error and select it as your answer. If there is no error, select 'No error (S)' as your answer.
(P) I did not like his (Q) comments on my paper (R) but I had no alternative as I had agreed to keep quite. (S) No error
Solution : The correct choice is the third option.
The correct term is "keep quiet", which means to remain silent or not speak. "Keep quite" is incorrect. Quite means completely or entirely, whereas quiet means making little or no noise.
Therefore, the correct sentence is: I did not like his comments on my paper, but I had no alternative as I had agreed to keep quiet.
Question : Directions: Select the option that represents the letters which, when sequentially placed from left to right in the blanks below, will complete the letter series. _ L _ _ K S _ T U _ S L _ _ K
Option 1: L U S K T U K
Option 2: U T S K T L U
Option 3: S T U L K T U
Option 4: K T U L U T S
Correct Answer: S T U L K T U
Solution : Given: _ L _ _ K S _ T U _ S L _ _ K
To fill the series we have to divide the series – _ L _ _ K / S _ T U _ / S L _ _ K Let's check each option – First option: L U S K T U K; L L U S K / S K T U T / S L U K K (No repeated pattern has been found) Second option: U T S K T L U; U L T S K / S K T U T / S L L U K (No repeated pattern has been found) Third option: S T U L K T U; S L T U K / S L T U K / S L T U K (SLTUK is repeated in the series) Fourth option: K T U L U T S; K L T U K / S L T U U / S L T S K (No repeated pattern has been found)
So, the series becomes→S L T U K S L T U K S L T U K. Hence, the third option is correct.
Question : Directions: Which of the options is the exact mirror image of the given figure when the mirror is held at the right side?
Solution : As per the mirror image properties, closer things appear close to the mirror in the reflection. Here, according to the information provided, the mirror is placed on the right side of the figure. So, the left side of the reflected image will appear as the right side, and the right side will appear as the left side. However, the top and bottom of the reflected image will remain the same. Thus, the correct mirror image of the given figure will be –
Hence, the third option is correct.
Question : A person covers a distance of 300 km and then returns to the starting point. The time taken by him for the outward journey is 5 hours more than the time taken for the return journey. If he returned at a speed of 10 km/hr more than the speed of going, what was the speed (in km/hr) for the outward journey?
Option 1: 15
Option 2: 20
Option 3: 30
Option 4: 25
Correct Answer: 20
Solution : Let the speed of the forward journey be $x$ km/hr. Speed of return journey will = $(x + 10)$ km/hr Time taken in return journey = $\frac{300}{(x + 10)}$ hours Time taken in forward journey = $\frac{300}{x}$ hours According to the question, ⇒ $\frac{300}{x} -\frac{300}{x+10} = 5$ ⇒ $\frac{300(x + 10) - 300x}{x(x + 10)} = 5$ ⇒ $300x + 3000 - 300x = 5x^2+50x$ ⇒ $3000 = 5x^2 + 50x$ ⇒ $5x^2 + 50x - 3000 = 0$ ⇒ $x^2 + 10x - 600 = 0$ ⇒ $x^2 + 30x - 20x - 600 = 0$ ⇒ $x(x + 30) - 20(x + 30) = 0$ ⇒ $(x - 20)(x + 30) = 0$ As speed cannot be negative, so $x=20$ km/hr Hence, the correct answer is 20.
Question : How many sites were chosen from India for the 2019 UNESCO Asia-Pacific Awards for Cultural Heritage Conservation?
Option 1: Five
Option 2: Four
Option 3: Two
Option 4: Three
Correct Answer: Four
Solution : The correct answer is Four.
India had four sites selected for the 2019 UNESCO Asia-Pacific Awards for Cultural Heritage Conservation. Among them, three are located in Mumbai—Flora Mountain, Keneseth Synagogue, and Gloria Church. The fourth site is the Vikram Sarabhai Library in Ahmedabad. The announcement of these awards took place in Malaysia in 2019.
Question : PA and PB are two tangents from a point P outside the circle with centre O. If A and B are points on the circle such that $\angle \mathrm{APB}=128^{\circ}$, then $\angle \mathrm{OAB}$ is equal to:
Option 1: 72°
Option 2: 52°
Option 3: 38°
Option 4: 64°
Correct Answer: 64°
Solution :
$\angle APB =128^{\circ}$ Let $\angle OAB = x$ $\angle PAB = 90^{\circ} - x$ Since PA and PB are tangents from the same external point P, ⇒ PA = PB $\therefore \triangle APB$ is an isosceles triangle. ⇒ $\angle PAB = \angle PBA = 90^{\circ} - x$ In $ \triangle APB$, $\angle APB + \angle PAB + \angle PBA = 180^{\circ}$ ⇒ $128^{\circ} + (90^{\circ} - x) + (90^{\circ} - x) = 180^{\circ}$ ⇒ $128^{\circ} = 2x$ ⇒ $x = 64^{\circ}$ Hence, the correct answer is $64^{\circ}$.
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