Theory of machines and design
Dear student, here the angular acceleration of both the shafts will be same
so, α1 = α2
=> ω1*r1 = ω2*r2
where r1 is the radius of pulley fitted on main spindle and r2 is the radius of pulley fitted on machine spindle.
=> 250*(d/2) = 25*(20/2)
=> d = 25*20/250 = 2 c.m.
Therefor diameter of the pulley to be fitted on main spindle is 2c.m.
All the best
Hope this helps
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