#5G
376 Views

58.5g of Nacl dissolved in 500ml of H²O .Calculate the normality?


Mega Omprakash 25th Jul, 2021
Answer (1)
Ayush 25th Jul, 2021

Hello Candidate,

The number of gram equivalents of solute is equal to the weight of solute added divided by the molar mass of solute or salt solution. The molar mass of NaCl is equal to 58.5, so the gram equivalent of solute is equal to 58.5/58.5= 1.

The volume of solvent is equal to 500ml or can be expressed as 0.5 litres. So, the formula of normality is equal to gram equivalent of solute / the volume of solvent in litres which is equal to 1/0.5= 2 Normal

Hope you found it helpful. If you have any further queries feel free to post it here!!

Related Questions

UEI Global, Hotel Management ...
Apply
Training & Placement Guarantee | Top Recruiters: The Oberoi, Taj, Lee Meridien, Hyatt and many more
VIT Bhopal University | M.Tec...
Apply
M.Tech admissions open @ VIT Bhopal University | Highest CTC 52 LPA | Apply now
Amity University | M.Tech Adm...
Apply
Ranked amongst top 3% universities globally (QS Rankings).
Amity University Noida MBA Ad...
Apply
Amongst top 3% universities globally (QS Rankings)
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
XAT- Xavier Aptitude Test 2026
Apply
75+ years of legacy | #1 Entrance Exam | Score accepted by 250+ BSchools | Apply now
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books