Dear student,

Due to Braking,

At = 0.5 m/s^2 ( At = Tangential acceleration )

Speed of the cyclist,v=27 km/hr = 275/18 = 7.5 m/s

Radius of the circular turn, r=80m

Centripetal acceleration (Ac) is given as:

Ac = v^2/r

Ac = ((7.5)^2)/80 = 0.7 m/s^2

Since the angle between Ac and At is 90degrees

Therefore, the resultant or net acceleration (A) is given by :-

A = (Ac^2 + At^2)^0.5

A = (0.7^2+0.5^2)^ 0.5 = 0.86 m/s^2