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a particle starts from rest has a constant accleration of 4m/s2 for 4s. it then retard uniformly for next 8s and comes to rest . average accleration during motion of particle is0


Ritesh 17th Sep, 2019
Answers (2)
Ronak Gala Student Expert 27th Oct, 2019

v = 0 m/s


u = 10 m/s


s = 20 m.


v^2 = u^2 + 2as


Or, 0 = 100 + 40a


Or, a = - 100 /40 = - 5/2.


.°. a = - 5/2 m/s^2


___________


Second case,


v = 0 m/s


u = 20 m/s


a = - 5/2 m/s^2


v^2 = u^2 + 2as


Or, 0 = 400 - 5s


Or, s = 400/5 = 80.


.°. The stopping distance will be 80 m.


Thank you.

ADITYA KUMAR Student Expert 27th Oct, 2019

Hello there!

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I am extremely sorry to tell you but you haven't completed your question,  what did not mention what is needed to be found in the question,  let me know what is to be found in the questions so that I can help you by giving you its solution.

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