Hello student cut off vary every year on various factors like the level of question in the entrance examination and total number of applicants in that examination. I request you to please help me with your preferable college you're concerned about so that I can check and provide you the exact information about cut off.

You can easily calculate and get your rank by using this formula

100 - (your total percentile) * 869010 /100

This year its expected that the cut off for general category students in Jee main will be around 89 percentile.

Eligibility NIT's, IIITs, IITs- Candidates must passed or appearing class 12 with physics chemistry and mathematics with minimum 75 percent marks aggregate from a recognized board.

Feel free to comment if you have any doubt

Good luck