51 Views

Can anyone give me the answer of this question of Physics of circular motion?


Tejas Gupta 7th Apr, 2019
Answer (1)
RUCHI RAJ 12th Jul, 2019

Hello Aspirant.

Since it's a frictionless surface, the total potential energy of the body will be converted to kinetic energy.

So, mgh=½mv^2

h=v^2/2g

Since the minimum velocity at the lowest point to complete the loop is √(5gr)

So, h= (5gD/2)/2g

Therefore the minimum height= 5/4D

Hope it helps.

Related Questions

UPES M.Sc Admissions 2026
Apply
Ranked #45 Among Universities in India by NIRF | 1950+ Students Placed 91% Placement, 800+ Recruiters
UPES B.Sc Admissions 2026
Apply
Ranked #45 Among Universities in India by NIRF | 1950+ Students Placed, 91% Placement, 800+ Recruiters
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
NIELIT University(Govt. of In...
Apply
Campuses in Ropar, Agartala, Aizawl, Ajmer, Aurangabad, Calicut, Imphal, Itanagar, Kohima, Gorakhpur, Patna & Srinagar
JSS University Mysore 2025
Apply
NAAC A+ Accredited| Ranked #24 in University Category by NIRF | Applications open for multiple UG & PG Programs
MAHE Online MBA
Apply
Apply for Online MBA from Manipal Academy of Higher Education (MAHE)
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books