Answers (2)
Anurag Khanna 22nd Jun, 2020

Hello Aspirant,

According to your percentile you can calculate your rank by using this formula -

100 - (your total percentile) 869010 /100

In your case, your rank must be around - 111,059

As cut off vary every year depending upon various factors like the level of question in the entrance examination, total number of applicants in that examination and so on. Therefore with this rank its difficult to get admission in CSE Branch and IT branch in VIT Mumbai, as we all know that seats are very limited and admission is directly based on merit rank in Maharashtra State Counseling.

You can check the previous year closing rank for CSE and IT branch of VIT Mumbai from the link given below :-

B.Tech/B.Arch Admissions OPEN

Apply to Amity University Noida B.Tech Admissions 2025

https://www.careers360.com/colleges/vidyalankar-institute-of-technology-mumbai/cut-off?college_id=2670&exam_sub_exam_id=2&ici=college_view_cutoffs&counselling_id=4433

You can also use JEE-Main College Predictor to predict your college according to your percentile and category. Link for the same is given below :-

https://engineering.careers360.com/jee-main-college-predictor

I hope this information helps you.

Good Luck!!

NILUTPOL Student Expert 22nd Jun, 2020
Hello,
The cutoff rank for JEE mains for VIT mumbai was around 55k for B.Tech CSE  and 75k for B.tech IT.
As you have scored 87 percentile in JEE mains your rank will lie between 117000 to 130000.
So you have no chances of getting a seat in B.tech CSE or IT.
Please visit this link to get a list of engineering colleges in Pune which accept jee mains score.
https://engineering.careers360.com/colleges/list-of-engineering-colleges-in-pune-accepting-jee-main
Hope it helps
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