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CO2} is linear triatomic molecule. The average K.E. at temperature T will be: D) 7KT / 2 C) 6kT / 2 B) 5kT / 2 A) 3kT / 2 what will be the ans.?? is A is the ans??? pls justify..


suprovo 20th Jul, 2022
Answer (1)
piyush263001 20th Jul, 2022

Hello,


It is very important to understand the concept of Degree of Freedom before you approach the question.


------- DOF or Degree of freedom in layman terms is basically no. Of ways in which a molecule can attain energy.

-------- So energy can be acquired by Translational motion, rotational motion and vibratory motion ( only at high temperatures).


-------- So, for a diatomic molecule and triatomic linear molecule like CO2 following DOF are associated with each form of motion:


• Translational motion - 3

• Rotational motion - 2

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• Vibratory Motion - 2 (Only at High Temperature)


-------- Also energy associated with 1 DOF as per Maxwell's Law of equipartition of energy = 1/2KT ( K = Boltzmann Constant)


--------- Hence total Energy for CO2 molecule at normal temperature is 5/2KT.


I hope you find the answer helpful.

Thank you.


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