Question : Directions: Four pairs of numbers have been given, out of which three are alike in some manner, while one is different. Choose out the odd one.
Option 1: 51 – 25
Option 2: 50 – 7
Option 3: 16 – 3
Option 4: 64 – 32
Correct Answer: 64 – 32
Solution : Let's check each option – First option: 51 – 25 51 + 25 = 76; 19 × 4 = 76; The sum of the pair is the multiple of 19. Second option: 50 – 7 50 + 7 = 57; 19 × 3 = 57; The sum of the pair is the multiple of 19. Third option: 16 – 3 16 + 3 = 19; 19 × 1 = 19; The sum of the pair is the multiple of 19. Fourth option: 64 – 32 64 + 32 = 96; The sum of the pair is not the multiple of 19.
So, the fourth option is different from the others. Hence, the fourth option is correct.
Application | Eligibility | Selection Process | Result | Cutoff | Admit Card | Preparation Tips
Option 1: 25 : 16 : 9
Option 2: 64 : 100 : 18
Option 3: 81 : 9 : 19
Option 4: 16 : 64 : 12
Option 1: 25 : 650
Option 2: 14 : 210
Option 3: 7 : 50
Option 4: 21 : 462
Question : Directions: Four number–pairs have been given, out of which three are alike in some manner and one is different. Select a different one.
Option 1: 48 – 81
Option 2: 64 – 100
Option 3: 25 – 36
Option 4: 16 – 49
Question : Directions: Four pairs of letter clusters have been given out of which three are alike in some manner, while one is different. Choose the odd one.
Option 1: NVH–KUK
Option 2: REA–ODD
Option 3: CWX– AVZ
Option 4: TXB–QWE
Question : Directions: Four pairs of letter–clusters have been given out of which three are alike in some manner, while one is different. Choose the odd one.
Option 1: XHEP–KVRA
Option 2: ARNI–RMIZ
Option 3: OLEV–EVOL
Option 4: TSRA–ZIHG
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