HI,

On the basis of following factors, the cut-off list is prepared:

Total number of candidates who will qualify JEE Main 2019

Total number of candidates who apply for JEE Advanced 2019

Total number of candidates appear for JEE Advanced 2019

Difficulty Level of Exam

Previous year cut-off trends

JEE Advanced Cut Off 2019 is the minimum marks that candidates have to score for admission into the undergraduate level programmes. Every year, the cut-off list will be declared by the conducting authority after the result declaration

Candidates have to score minimum percentage of marks, in order to be included in the rank list. Below we have listed minimum no. of marks both subject wise and aggregate.

Maximum aggregate marks: 372 (186 Qualifying Marks)

Maximum marks in Physics: 124 (62 Qualifying Marks)

Maximum marks in Chemistry: 124 (62  Qualifying Marks)

Maximum marks in Mathematics: 124 (62 Qualifying Marks)

Hello Sir. JEE Advanced Cutoff 2019 consists of the minimum marks or ranks that the candidates will be required to secure to move further in the admission process. There will be two cutoff released by the authorities - qualifying cutoff and admission cutoff. Minimum Aggregate Marks is 126 and Minimum Aggregate Marks (Revised) is 90.