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Hello Aspirant,
It would be difficult to tell you the category rank, You may calculate your general rank by using the formula.
100 - your total percentile score is the percentage of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100 Using the formula (100 - your total score) X 869010 /100.
Your probable rank will be 30, 936.
With this percentile, You can have the chances to get-
B.Tech/B.Arch Admissions OPEN
National Institute of Technology Tiruchirappalli- Civil, Chemical, National Institute of Technology Karnataka Surathkal, National Institute of Technology Warangal, National Institute of Technology Rourkela, National Institute of Technology Calicut-ECE, Mechanical.
To know your other admission possibilities, You can use JEE Main College Predictor tool.
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Good Luck!
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