Hello there,
The cut-off rank for MNIT Jaipur for CSE was 1721 for OBC under Home State Quota. Now, for this rank, you need to score atleast 98.5 percentile, or 99.5 to be on the safe side. The exact percentile cannot be said since the cut-off rank changes every year depending on the difficulty of the paper, and the number of candidates appearing for it.
Hope this answer helps you.
Good luck!!

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