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I got 92.93 percentile in jee main with obc -ncl which nit and branch is suitable for me


JEE Main 2026 Ques & Sol's: 28 Jan: Shift-2 | Shift-1 | All Shift (Session 1)

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swamiharishswami 14th Aug, 2021
Answer (1)
ADITYA KUMAR Student Expert 14th Aug, 2021

Hi

Your profile suggests that your home state is Rajasthan

With 92.93 percentile


Your obc rank will be around 19k-  22k

With above  rank, you have very low  chances in NITs .

For example,

Closing rank for some of the lower NITs for OBC  category under other state is provided below in 6th round of josaa counselling 2020 :-

B.Tech/B.Arch Admissions OPEN

Apply to Amrita University B.Tech 2026

  • NIT Mizoram ,civil engineering :- 14730 obc rank

  • Nit nagaland :- Electronics and Instrumentation Engineering (4 Years, Bachelor of Technology) :-  15340 obc rank

  • National Institute of Technology AgartalaProduction Engineering (4 Years, Bachelor of Technology :- 15659  obc rank


You can verify the above at

https://josaa.nic.in/Result/Result/currentorcr.aspx

So, to get a seat in NIT you should get at least around 15000 OBC rank i. e around 95 percentile .


This has been predicted on the basis of past year data but  cut off/closing rank for colleges keeps changing every year depending upon many factors like number of students that appeared in the examination, difficulty level of the JEE main question paper for different shifts etc

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

To improve your score ,you should focus on your preparation go through previous year question papers ,mock test papers and to help you in your preparation we have jee main knockout out for you, for which  is provided below


https://learn.careers360.com/knockout-jee-main

To help you further,

To give you an idea of qualifying cut off, JEE mains 2020  qualifying  CUT OFF percentile to be eligible for jee advanced is given below for different category

>>>> General :-     90.3765335

>>>> GEN-EWS :-  70.2435518

>>>> OBC-NCL :-  72.8887969

>>>> SC     :-           50.1760245

>>>> ST :-                39.0696101

>>>> PwD :-            0.0618524

You can check the same at our page the link is provided below

https://engineering.careers360.com/articles/jee-main-cutoff


Thankyou

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