268 Views

i got 94.44 percentile.in jee mains January 2020 .can i get admission in nit trichy


sudhabalan1979 18th Dec, 2019
Answers (3)
Payal 27th Jan, 2020

Hii aspirants

let me clear your doubt

to know which college you will get according to your jee main rank you can visit the site

here you will get all the information regarding which college is best for you with this percentile or rank.

I hope my answer will help you out

Good luck

Rishi Garg 27th Jan, 2020

You can calculate your rank in JEE Main Paper 1 using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 1 (Jan) are around 869000, your rank will be around 48300. However as the no. of students in April changes, your rank will change according to that.

With this rank, there are very less chances of getting admission into NIT Trichy but if home state quota applies to you for this institute, then there may be some chances based on that.

To get the list of all Institutes which you may get with this rank, kindly use the college predictor through the link given:

For more information regarding counseling, cutoffs, etc.. you can use the B.Tech companion from the link given below:

https://www.careers360.com/btech-companion

JEE Main College Predictor

Predict your top engineering college admission chances based on your JEE Main All India Rank & NTA Score.

Use Now
Sharon Rose Student Expert 27th Jan, 2020
Hello,
You have not mentioned you category and state, it will be helpful if you can tell us your category and state because the cut off is different for each category, also the cut off for home state candidates and other state candidates is different.Please mention whether you the given percentile is for paper 1 or paper 2.

However, you can calculate your expected rank using the formula given below
(100-your total percentile)*869010/100
869010 is the total number of candidates appeared in JEE main January session paper 1.
(100-94.44)*869010/100=48316
So your expected rank will be around 48316.
It is expected that the number increase to 1200000 in April session.So it will become (100-your total percentile)*1200000/100

If it is paper 2 then it can be calculated using the formula given below
(100-your total percentile)*112679/100
112679 is the total number of candidates appeared in JEE main January session in paper 2.

Know More About

Related Questions

Amity University, Noida B.Tec...
Apply
Asia's Only University with the Highest US & UK Accreditation
UPES B.Tech Admissions 2024
Apply
Ranked #52 among universities in India by NIRF | Highest CTC 50 LPA | 100% Placements | Last Date to Apply: 31st May
Jain University B.Tech 2024
Apply
100% Placement Record | Highest CTC 42 LPA | NAAC A++ Accredited | Ranked #68 in India by NIRF Ranking 2023 | Last Date to Apply: 17th May
ICFAI University Hyderabad B....
Apply
Merit Scholarships | NAAC A+ Accredited | Top Recruiters : E&Y, CYENT, Nvidia, CISCO, Genpact, Amazon & many more
Alliance University B.Tech 2024
Apply
800+ Recruitment Partners
Manav Rachna University B.Tec...
Apply
MRIIRS accredited A++ grade by NAAC | 39000+ Alumni network
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books