Hello Aspirant,

It's difficult to tell you the exact rank or qualifying score for JEE Advanced Eligibility. With this score the chances should be decent to qualify the exam.

You may calculate your expected rank by this formula

100 - your total percentile score is the percentage of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100

Using the formula
(100 - your total score) X 869010 /100

Your probable rank will be 14,773.

Based on your percentile you can have the chances to get Malaviya National Institute of Technology Jaipur-B.tech Chemical Engineering, Civil Engineering, National Institute of Technology Calicut, Visvesvaraya National Institute of Technology Nagpur, Sardar Vallabhbhai National Institute of Technology Surat- Civil & Chemical engineering Etc.

You can also use JEE Main College Predictor tool to know your other admission possibilities.

Good Luck!

Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 14773. Use our College predictor to analyse your chance at possible colleges: https://engineering.careers360.com/jee-main-college-predictor?

Hi aspirant,

Your marks seem good enough to get a seat in IITs, NITs and CFTIs. Because your score is higher than the cut off marks required for the all categories. Then other colleges which accept JEE score also accept you based on the reservations.

To predict the colleges use,

Hope it helps.