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To caculate your rank with the help of your percentile, we should use the formula:
(100-your total percentile)*869010/100. Going by this formula, your rank will be 54313. Now this is for January session. If the no.of Candidates appearing for JEE Mains April session is increased to 12,00,000 then your final rank is calculated using the formula: (100 - your total score) X 12,00,000/100.
With this rank, chances in good branches might in NITs and IIITs might be less. But should you plan on appearing for JEE Advanced, you will qualify as the expected qualifying percentile is 85 and above.
If you look at the previous cut offs IIIT Kanchipuram as mentioned here:
CSE:
15862
ECE:
20778
ME:
29180
Smart Manufacturing:
38737
B. Tech-M.Tech
Mechanical Engineering in Product Design
38623
Advanced Manufacturing
40529
Computer Science and Engineering (Integrated Dual Degree)
23855
B. Tech. -M.Tech Electronics Communication Engineering
with specialization in Communication Systems Design
32339
B. Tech-M.Tech Electronics and Communication Engineering
with specialization in VLSI Design
29735
Though cut offs change ever year, with your rank, it might be difficult for IIIT. Now to predict colleges, please use our college predictor:
JEE Main College Predictor – Know your College Admission Chances Based ...
Discover your college admission chances with the JEE Main 2026 College Predictor. Explore NITs, IIITs, CFTIs and other institutes based on your percentile, rank, and details.
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