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I have got 95.47 percentile in january session of jee mains 2019.Do I need to seat for the april session too??m i eligible 4 top 10 NITs?


Debasmita Mukherjee 25th Feb, 2019
Answer (1)
UTKARSH DUBEY 25th Feb, 2019
Hello Debasmita,
Your rank will be 38505 as per our rank predictor formula.
Rank predictor formula =((100 - your percentile)/100)*Total number of candidate.
Total number of candidate = 850000.
Your rank range 36000-40000 .
With this percentile you able to get home state NIT with help of home state quota.
No candidate you not able to get seat in top 10 NIT with this percentile.
For getting top 10 NIT your percentile should be more than 98.
Those candidate whose percentile is above 98 are going to be under AIR 10000.
With under 10000 rankings candidate able to fetch seat in top 10 NIT and other good IIIT.

To know more about percentile system follow the link below:https://engineering.careers360.com/articles/jee-main-normalisation-process-how-scores-are-calculated/amp

To know through Video follow the link below:https://youtu.be/lXb58NIhSRE

If you have any questions remain than comment below.
Good luck...

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2 Comments
Comments (2)
25th Feb, 2019
General candidate i belong from.. And m from Kolkata,  west Bengal 
Reply
28th Feb, 2019
Hello candidate you are only eligible for Fetching seat in home state NIT with your percentile.
To get top 4 NIT your percentile should be above 98 percentile than your general rankings is under 10000 with help of which you can fetch seat in top NIT.


Hope this helps you.

If you have any questions remain than comment below.
Good luck...
Reply
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