Hi,

Nits take admission on the basis of jee main merit / ranking.

With the mentioned percentile you can calculate your rank by using formula

100 - your total percentile score is the percentage  of people ahead of you. 44517 are the number of candidates appeared for January exam.

So rank formula for you will be

(100 - 97) X 44517/100.

With this you can expect a rank around 1335.

If we look at the previous years cutoff for nit bhopal it is found that generally the closing rank for a general category lies between 1000 - 8000 for home state and other state qouta.  However the cutoff for every year depend on the several factors like number of student appeared, difficulty level of exam etc. So you will find that each year the cutoff varies.

You can check the cutoffs in more details for each year through the link https://engineering.careers360.com/articles/jee-main-cutoff-for-manit-bhopal/amp

So with this score you can expect a seat in B.planning section in general category.

Best of luck.