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I HAVE GOT 99.6122553% ON JEE MAINS 2019 12 JAN EXAM. WHAT WILL BE MY RANK AND CAN I GET CS IN TOP NITS OR IIITS


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Debasish Dey 20th Jan, 2019
Answer (1)
Sai 20th Jan, 2019

Hello Debasish Dey..Firstly congrats for that good percentile.

Percentile= (marks you got*100)/(toppers marks in that session).

According to careers360 rank formula, 

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 3,391.

As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.

So according to expected rank of yours, so you are eligible for jee advanced.

Yes you get good colleges check official josaa site for opening and closing ranks for previous years.

Hope this helps you. All the best

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Apply to Amrita University B.Tech 2026

1 Comment
Comments (1)
Sai
25th Jan, 2019
Need a small correction for my answer,percentile=(100*no of candidates who scored equal or less than you in that session)/(Total no of candidates appeared in that session).
Reply
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