Hello Aspirant,

Shiv Nadar University, Delhi, being the private institution provides decent chances for admission in top branches on little low percentiles in JEE-Main but since you have not mentioned your category so considering it as General, if any other than please mention it. So being a general category candidate you have decent chances to get admission in CSE branch in Shiv Nadar University on such percentile in JEE-Main through their own counselling for JEE-Main quota but the cut-off keeps changing every year depending upon various factors so there might be some chances that you may not get the required so then you can try in Management quota if the university have.

According to the mentioned percentile your rank is expected to be in the range of 110484 - 124200 , you can check out marks Vs ranks Vs Percentile from the link given below :-

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

Or

You can also use JEE-Main Rank Predictor to predict your rank :-

To have a list of all those colleges which you can get based upon your marks, category, and state you can use JEE-Main College Predictor:-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

I hope this information helps you.

Good Luck!!

Dear Student,

as per the cutoff for the previous years, the chances for you to be able to secure a seat at Shiv Nadar, University is less. However, there are other colleges where you can get admission based on your secured percentile in JEE Mains for the branch of CSE,

• Rajarambapu Institute of Technology, Kolhapur
• Lakshmi Narain College of Technology, Bhopal
• Terna Engineering College, Mumbai
• D.Y. Patil School of Engineering, Pune
• Datta Meghe College of Engineering, Navi Mumbai
• Lokmanya Tillak College of Engineering, Mumbai
• Techno Engineering College, Indore

For further details on colleges suitable for you as per your preference and percentile kindly visit the link given below.

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer