Question : If $\sin \theta+\cos \theta=\frac{1}{29}$, then find the value of $\frac{\operatorname{sin} \theta+\operatorname{cos} \theta}{\operatorname{sin} \theta-\operatorname{cos} \theta}$.
Option 1: $\frac{1}{41}$
Option 2: $\frac{43}{29}$
Option 3: $\frac{41}{29}$
Option 4: $\frac{1}{43}$
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Correct Answer: $\frac{1}{41}$
Solution : Given: $\sin \theta+\cos \theta=\frac{1}{29}$ We know that $\sin \theta+\cos \theta=\frac{1}{29}$ Squaring both sides, $(\sin \theta+\cos \theta)^2=\frac{1}{29^2}$ ⇒ $1+2\sin \theta\cos \theta=\frac{1}{841}$ ⇒ $2\sin \theta\cos \theta=\frac{1}{841}-1=-\frac{840}{841}$...(i) Now, $(\sin \theta-\cos \theta)^2=1-2\sin \theta\cos \theta$ From equation (i) $(\sin \theta-\cos \theta)^2=1-(-\frac{840}{841})=\frac{1681}{841}$ ⇒ $(\sin \theta-\cos \theta)=\sqrt{(\frac{1681}{841})}=\frac{41}{29}$ ⇒ $(\sin \theta-\cos \theta) =\frac{41}{29}$ ⇒ $\frac{\operatorname{sin} \theta+\operatorname{cos} \theta}{\operatorname{sin} \theta-\operatorname{cos} \theta}=\frac{1}{29}×\frac{29}{41}=\frac{1}{41}$ Hence, the correct answer is $\frac{1}{41}$.
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Question : If $\frac{\sin \theta-\cos \theta}{\sin \theta+\cos \theta}=\frac{4}{5}$, then the value of $\frac{\operatorname{cosec}^2 \theta}{2-\operatorname{cosec}^2 \theta}$ is:
Option 1: $\frac{16}{25}$
Option 2: $\frac{40}{41}$
Option 3: $\frac{41}{40}$
Option 4: $\frac{31}{30}$
Question : If $\operatorname{tan} \theta=\frac{3}{4}$, then find the value of expression $\frac{1+\operatorname{sin} \theta}{1-\operatorname{sin} \theta}$.
Option 1: 4
Option 2: 3
Option 3: 8
Option 4: 5
Question : What is the value of $\frac{\sin \theta+\cos \theta}{\sin \theta-\cos \theta}+\frac{\sin \theta-\cos \theta}{\sin \theta+\cos \theta}$?
Option 1: $\frac{1}{\left(\sin ^2 \theta-\cos ^2 \theta\right)}$
Option 2: $2\left(\sin ^2 \theta-\cos ^2 \theta\right)$
Option 3: $\frac{2}{\left(\sin ^2 \theta-\cos ^2 \theta\right)}$
Option 4: $\sin ^2 \theta-\cos ^2 \theta$
Question : If $\sin \theta-\cos \theta=\frac{1}{5}$, then find the value of $\sin \theta+\cos \theta$.
Option 1: $\frac{5}{7}$
Option 2: $\frac{7}{5}$
Option 3: $\frac{5}{3}$
Option 4: $\frac{3}{5}$
Question : If $\frac{\sin\theta+\cos\theta}{\sin\theta-\cos\theta}=3$, then the value of $\sin^{4}\theta$ is:
Option 1: $\frac{2}{5}$
Option 2: $\frac{1}{5}$
Option 3: $\frac{16}{25}$
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