Question : If $\operatorname{tan} heta=\frac{3}{4}$, then find the value of expression $\frac{1+\operatorname{sin} heta}{1-\operatorname{sin} heta}$.
Option 1: 4
Option 2: 3
Option 3: 8
Option 4: 5

Question

Question : If $\operatorname{tan} heta=\frac{3}{4}$, then find the value of expression $\frac{1+\operatorname{sin} heta}{1-\operatorname{sin} heta}$.

Option 1: 4

Option 2: 3

Option 3: 8

Option 4: 5

Team Careers360 · Accepted Answer

Correct Answer: 4

Solution :
Given: $ an heta=\frac{3}{4} =\frac{Perpendicular}{Base}$
Using Pythagoras' theorem,
$AC=\sqrt{AB^2+BC^2}$
⇒ $AC=\sqrt{3^2+4^2} =5$
$\sin heta =\frac { ext {Perpendicular}}{ ext {Hypotenuse} } = \frac{3}{5}$
Now,
$\frac{1+\sin heta}{1-\sin heta} = \frac{1+\frac{3}{5}}{1-\frac{3}{5}} =\frac{8}{2}=4$
Hence, the correct answer is 4.

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Question : If tanθ=34, then find the value of expression 1+sinθ1−sinθ.Option 1: 4Option 2: 3Option 3: 8Option 4: 5

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Question : If $\tan θ = \frac{3}{4}$ , then find the value of expression $\frac{1 + \sin θ}{1 - \sin θ}$ .
Option 1: 4
Option 2: 3
Option 3: 8
Option 4: 5