Hello Aspirant,

See the percentiles have been declared by NTA on July 11th, 2022 as a result of session-1 of JEE-Main 2022 so you can check that out from your respective result.

And your rank can only be determined by your percentile so kindly help us with the percentile that you have received in your scorecard of session 1 of JEE-Main 2022 so that we can help you to predict your rank for JEE-Main 2022.

Also you can check out marks Vs ranks Vs Percentile from the link given below :-

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

To have a list of all those colleges which you can get based upon your JEE-Main ranks or score you can use JEE-Main College Predictor:-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Or

You can also check out our Engineering Counselling Subscription package in which you get B.Tech companion tool which will guide you in all your counselling and admission related issues and along with this you will be getting 3 one-to-one counselling sessions by our experts :-

https://www.careers360.com/campaign/Engineering-Counseling-Subscription

I hope this information helps you.

Good Luck!!

hello aspirant,

As you are a General Category Student, and you have mentioned that you are getting 98 marks in JEE mains session examination, then your predicted overall percentile score under this marks in jee mains will be around 92.19 - 94.65 and your overall rank under general category will be around 71610 - 80500 .

Now, please note that the above prediction of JEE mains Rank and Percentile score is totally based on the previous year Cutoff which may vary this year as the JEE mains Cutoff keep changing every year.

To know more about the JEE mains Cutoff, you can follow the below mentioned link : https://engineering.careers360.com/articles/jee-main-cutoff

To know about your chances of admissions in other colleges, you can follow the below mentioned link to know more : https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp

I hope that this will help.