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in ydse ,if the width of the slits are in the ratio of 4:9 then the ratio of intensity of Maxima to the intensity at minima will be


Shashank shekhar 25th Feb, 2020
Answer (1)
Ayush Mishra 25th Feb, 2020

Shashank, the answer to your query is 25:1 that is, the ratio of intensity of maxima to the intensity of minima is 25:1 . Now let us understand the solution of this query.

It is given that the slit widths are in ratio 4:9

Now, the width (W) is directly proportional to intensity (I), so W1/W2 = I1/I2

Therefore, we get the ratio I1/I2 = 4/9

Now, the intensity is proportional to the square of the amplitude also, so

I1/I2 = (A1)^2/ (A2)^2

So, the ratio of amplitude is A1:A2 is 2:3

Now, the intensity of maxima is  (A1+A2)^2  = (2+3)^2 = 25

and the intensity of minima is     (A1-A2)^2 = (2-3)^2 = 1

Therefore the ratio of intensity of maxima to that of minima is 25:1

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