The width of one of two slits in YDSE is d while that of the other slit is xd If the ratio of the max to min intensities in the interference pattern on screen is 9:4 what is valie of x
Hello,
If one slit in Young’s Double Slit Experiment (YDSE) has width d and the other has width xd, the ratio of the maximum intensities of the two slits is proportional to the square of their widths. Therefore, the ratio of maximum intensities will be 1 to x squared.
Hope this helps you.



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