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MIT CHENNAI, UG aerospace engineering admission procedure ?


Amreshwari Singh 1st Mar, 2019
Answers (2)
Aashish Pandey 10th Apr, 2019
Hyy Amreshwari
The admission procedure for UG aerospace engineering in MIT, Chennai is as follows:-
>The basic minimum eligibility for UG courses in MIT is 10+2 in Science stream with 50% marks in PCM.
>Basic Admission Criteria is through TNEA Counselling/TANCET/GATE/Merit
>Application forms are available both online and offline. Other states candidates can apply for BE/B.Tech course online through TNEA website.
>Selection Process is throughTNEA Single Window Counselling.

And cut off are as follows
For TNEA 2018
General
starting rank -146
End rank-1295
2 Comments
Comments (2)
11th Apr, 2019
What does this "rank" means ?
Is this is based on a entrance exam or just counseling ?
Reply
11th Apr, 2019
Rank means like there are 10,000 people in the list and there are only 800 seats available... Soo they will start taking through rank procedure
And it is totally based on entrance test
Reply
sunidhi suri 10th Apr, 2019
Hey,
In MIT Chennai , for UG in  aerospace engineering you need to fill the application forms that are available both offline and online.
The basic eligibility criteria is:
10+2 in science stream with minimum 50% marks in pcm
The ug candidate are selected on the basis of TNEA counseling.
Admission to ug course is subjected to merit and rank secured by candidates in Tamil Nadu engineering admission (TNEA) counseling.
Candidates who have been shortlisted are allotted courses based on the merit . The admission procedure remains same for all UG courses offered by Madras Institute of Technology.

The selection of candidates will be based on the marks obtained in the prescribed subjects reduced to 200 (Mathematics  100, Physics + Chemistry  100 in the qualifying examination)
This is the admission process.
All the best
1 Comment
Comments (1)
10th Apr, 2019
Is TNEA conduct examination or just 12th result counseling?
Reply

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