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Particular integral of 'e' raise to the power e ki power x


Amit 29th Jan, 2019
Answer (1)
Debosmitha Bhattacharyya Student Expert 29th Jan, 2019

Hello Amit,

The solution to your question, using the exponential integral function, is Ei(e to the power x)+C.

If you do a substitution where u=e to the power x and thus du=e to the power x dx, your integrand becomes

e to the power u /u du, so the definition of the exponential integral can be applied and the integral becomes Ei(u)+C=Ei(e to the power x)+C.

Hope this helps.

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