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The acceleration potential for a x-ray machine is 50000 volts. The shortest wavelength present in the radiation is


Padala Shivani 27th Jun, 2019
Answer (1)
Abhijit Kundu 27th Jun, 2019

Hey,

We can determine the minimum wavelength of emitted x-rays, using the following formula:

λmin=hc/eVλmin=hc/eV

Where h is Planck’s constant, c is speed of light and eV the applied potential (for this purpose, the same as KV).

So, in your case it would be:

λmin=1.23984193/50=0.0247968386pm

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