Question : The area of a rhombus is 256 square cm, and one of its diagonals is twice the other in length. The length of its larger diagonal is:
Option 1: 32 cm
Option 2: 16 cm
Option 3: 48 cm
Option 4: 24 cm
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Correct Answer: 32 cm
Solution : Let the first diagonal be $x$ and the second diagonal be $2x$. Area of rhombus = $\frac{1}{2}\times$(Product of the diagonals) $256 = \frac{1}{2}\times x \times 2x$ ⇒ $256 = x^2$ ⇒ $x=16$ So, the length of the larger diagonal = 2 × 16 = 32 cm Hence, the correct answer is 32 cm.
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Question : The perimeter of a Rhombus is 60 cm and one of its diagonal is 24 cm. The area of the Rhombus is:
Option 1: 108 sq.cm
Option 2: 216 sq.cm
Option 3: 432 sq.cm
Option 4: 206 sq.cm
Question : The diagonals of a rhombus are 12 cm and 16 cm, respectively. The length of one side is:
Option 1: 8 cm
Option 2: 6 cm
Option 3: 10 cm
Option 4: 12 cm
Question : The area of a rhombus having one side 10 cm and one diagonal 12 cm is:
Option 1: $48\text{ cm}^2$
Option 2: $96\text{ cm}^2$
Option 3: $144\text{ cm}^2$
Option 4: $192\text{ cm}^2$
Question : The diagonal of the square is $8 \sqrt{2}$ cm. Find the diagonal of another square whose area is triple that of the first square.
Option 1: $8 \sqrt{5}$ cm
Option 2: $8 \sqrt{3}$ cm
Option 3: $8 \sqrt{2}$ cm
Option 4: $8 \sqrt{6}$ cm
Question : The lengths of the diagonals of a rhombus are 24 cm and 10 cm, then the perimeter of the rhombus (in cm) is:
Option 1: 52
Option 2: 56
Option 3: 68
Option 4: 72
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