Question : The diagonal of the square is $8 \sqrt{2}$ cm. Find the diagonal of another square whose area is triple that of the first square.
Option 1: $8 \sqrt{5}$ cm
Option 2: $8 \sqrt{3}$ cm
Option 3: $8 \sqrt{2}$ cm
Option 4: $8 \sqrt{6}$ cm

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Question : The sum of the length and breadth of a rectangle is 6 cm. A square is constructed such that one of its sides is equal to a diagonal of the rectangle. If the ratio of areas of the square and rectangle is 5 : 2, the area of the square (in cm²) is:

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Answer 1

Correct Answer: $8 \sqrt{6}$ cm

Solution : Given, Diagonal = $8 \sqrt{2}$
$∴$ Side = $\frac{8 \sqrt{2}}{\sqrt{2}} = 8$ cm
⇒ Area of this square = $(8)^{2} = 64$ cm ²
The Area of the Second square is triple the first one.
⇒ Area of the second one $= 64 \times 3$
$∴$ Side of the 2nd square $= \sqrt{64 \times 3} = 8 \sqrt{3}$
⇒ The diagonal 2nd square $= \sqrt{2} \times 8 \sqrt{3} = 8 \sqrt{6}$ cm
Hence, the correct answer is $8 \sqrt{6}$ cm.

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Question : The diagonal of the square is 82 cm. Find the diagonal of another square whose area is triple that of the first square.Option 1: 85 cmOption 2: 83 cmOption 3: 82 cmOption 4: 86 cm

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Question : The diagonal of the square is $8 \sqrt{2}$ cm. Find the diagonal of another square whose area is triple that of the first square.
Option 1: $8 \sqrt{5}$ cm
Option 2: $8 \sqrt{3}$ cm
Option 3: $8 \sqrt{2}$ cm
Option 4: $8 \sqrt{6}$ cm