97 Views

The number of real roots of the equation x^2-3x +2=0 is ?


tiwaripragati0809 21st Oct, 2018
Answer (1)
Vikas gehlot 22nd Oct, 2018

First, we will calculate Discriminant:

D=b^2-4ac

Here a=1,b=-3,c=2

therefore D=(-3)^2-4*1*2

              D=9-8

              D=1

Since Discriminant is greater than zero it means two real and discrete roots.

Now the roots are    3+1/2 and 3-1/2

That is the roots of the given equation are 2 and 1

That is equation has two real roots.

Related Questions

Amity University-Noida B.Sc A...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
RV University, Bangalore | B....
Apply
Highly qualified faculty from diverse academic backgrounds. Global exposure via partnerships with top international universities
Apollo Healthcare Academy
Apply
Get Job-Ready with New-Age Allied Health Programmes
VIT Chennai B.Sc. Admissions ...
Apply
#14 in India by NIRF Ranking | Institution of Eminence by Govt. of India | Scholarships Available
Emversity Allied Health Programs
Apply
Get Job Ready in Healthcare | Employability-Focused Programs
Navrachana University B.sc Ad...
Apply
Ranked as the 3rd Best Private University in Gujarat by Education World
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books