the ratio of population of two energy levels is 1.059 find the wavelength of light emitted by spontaneous emission at 330k

the ratio of population of two energy levels is 1.059 find the wavelength of light emitted by spontaneous emission at 330k

Dear Aspirant,

We know that, N2/N1= population ratio = 1.059*10^-30 & T=330K, similarly we are supposed to find lambda(wavelength)

Also,

N2/N1 = e^(-E/K*T)

Taking log on Both sides,

Log(N2/N1) = -E/K*T = [(-h*rho)/(K*T)]

rho = c/lambda

So, after rearranging we get,

Log (N2/N1) = {(-h*c)/(K) * (1/lambda*T)} after solving this through logarithmic functions, you will get the answer of lambda = 632.8mm

Kindly understand the answer by solving by your own too. Hope it helps you.

Thanks.