Hi,

B.ed in distance mode is provided by many institutions in india. Some of which are -

Annamalai University Directorate of Distance Education

Indra gandhi open university

Andhra university

Yashwant rao chavan mukt vidyapith

Sri Venkateswara University

Tamil nadu state open university

Jamia Millia islamia- center for distance and open

Hello

The focal length of the lens is -12 cm.

Hello!

No need to worry for the gap. You are eligible for doing distance MBA. Here I'm listing a few top colleges to consider for distance mba:

1) Symbiosis distance mba (mat/cmat/cet/Studentsgmat/cat/those who have not appeared in any of the State Level or equivalent entrance test at State or National

Hello

According to the question, the length  is 3 √ 2

Hello Surya,

I guess your question is incomplete, as the figure is missing. The radial distance is not mentioned.

Kindly repost your question with sufficient data.

Hello Sunil,

Your question is quite simple, the answer to your problem can be obtained by using the formula,

E*2*pi*d*epsilon=lambda

where epsilon is the permitivitty of free space, and lambda is the linear charge density.

Substitute the values, as given in the question,

E=9*10^4 N/C

pi=3.14

epsilon=9 × 10 ⁹

Hello,

The programs offered in Dr AER Degree and PG College, Tirupati are BSc, BBA, BCom,MSc.

All are offered in regular mode only.

The college doen't have official website, so you can check out the following link for more details regarding this-

https://www.careers360.com/colleges/dr-aer-degree-and-pg-college-tirupati

Hi Candidate,

The free fall distance is s which is experiencing a force of F equal to the mass of without the body, any external force in a certain time.

Now as we have a frictional force of F/2, equals to half of the weight in the same certain time,

Hello!!!!

Hope you are doing great!!!

Refraction through parallel slab = s=t(1-1/ μ )

s= shifting of object from slab

t=thickness of slab

μ =Refractive index of slab

F=10/2=5

Due to glass plate shift

s=t

(1-1/ μ )

=1.5

(1-2/3)

=0.5

New u=9.5cm

Using lens formula

1/v=1/f+1/u

1/v=1/5+1/-9.5

1/v=4.5/9.5*5

v=10.55cm