A JEE Mains score of 77 percentile indicates that you may have a moderate chance of qualifying for BITSAT, depending on the subjects and preparation you focus on. BITSAT is an online test with sections on Physics, Chemistry, Mathematics, English Proficiency, and Logical Reasoning. It’s crucial to strengthen your fundamentals in these areas. Aim for a score of 270+ for good chances in popular branches at BITS campuses.

For more details you can visit the link given below:

https://engineering.careers360.com/articles/bitsat-preparation-tips

Hello student,

I would suggest that you start upgrading your preparation for JEE Main second session. BITSAT questions are easier than JEE Main and require recollection of the appropriate formulae. The questions asked in JEE Main are more conceptual and require deep knowledge of concepts and techniques. So, a student preparing for JEE Main can easily appear for the BITSAT exam as well. The major difference in the syllabus of the two exams is the presence of English Proficiency and Logical Reasoning in the BITSAT.

What you can do is, alongwith JEE Preparation, you can also start preparing for Eng. and logical reasoning. That ways, you’d be easily able to cover both the exams.

While JEE Main is for admission in government engineering colleges, central and also for several states. BITSAT is only for the various campuses of one of the private colleges in India. So JEE definitely opens up more options.

If you want to check your rank range based on your percentile, then you can refer to the Careers360 JEE Main Rank Predictor: https://engineering.careers360.com/jee-main-rank-predictor?

If you need more information regarding which colleges you would be eligible for based on your marks and details, then you can refer to the Careers360 JEE Main College Predictor: https://engineering.careers360.com/jee-main-college-predictor?

Hello aspirant,

Hope you are doing great.

So coming to your question, YES, you are completely eligible to give the BITSAT exam. Recently the government has approved that open schooling is equal to regular schooling and students who have passed through open schooling are completely eligible for the entrance exams such as BITS, JEE Mains etc.

Hope this helps!

Hello aspirant,

Qualifications for BITSAT:

• The class 12 or equivalent test (from any state or central board of school education) must have been passed by the candidates.
• In the qualifying exam, they had to have received at least 75% of the possible points in Physics, Chemistry, and Mathematics/Biology.
• They should have received 60% grades in each of the three topics individually in addition to the 75% total.

So if you will not get 75% you will not be eligible.

Thank you

Hope this information helps you.

Correct Answer: (337, 311, 18)

Solution : Given:
(182, 156,13); (238, 212,15)

Add and subtract 13 from the square of the third number, to get the first and second number respectively –
⇒ (182, 156, 13)→13² + 13 = 182; 13² – 13 = 156
⇒ (238, 212, 15)→15² + 13 = 238; 15² – 13 = 212
Let's check each option –

First option: (370, 348, 19)→19² + 13 = 374 ≠ 370; 19² – 13 = 348
Second option: (336, 302, 17)→17² + 13 = 302 ≠ 336; 17² – 13 = 276 ≠ 302
Third option: (142, 126, 11)→11² + 13 = 134 ≠ 142; 11² – 13 = 108 ≠ 126
Fourth option: (337, 311, 18)→18² + 13 = 337; 18² – 13 = 311

So, only the fourth option follows the same pattern as the given set of numbers. Hence, the fourth option is correct.