Hi Student,

Thank you for reaching out!

Yes , securing admission to Class 11 is absolutely possible after passing Class 10 from a recognized board like CBSE, ICSE, or state boards.
The process typically starts after Class 10 results are declared.

Eligibility requires a minimum of 33-40% aggregate in Class 10, although competitive schools or streams (such as Science or Commerce) may demand 50-75% in relevant subjects like mathematics or science. For instance, CBSE schools often require 60%+ for science streams.

The admission process varies by board and state.

Required documents include the Class 10 marksheet, transfer certificate, birth certificate, and category certificate (if applicable).

For more information, click on the link below:
https://school.careers360.com/boards/cbse/cbse-class-11-admission

All the best.

Thank you.

Regards,
Careers360 Team

Hello Pranjal!

A score of 136 in the MET (Manipal Entrance Test) is a decent score, but CSE with specializations like AI, Data Science, or Mathematics and Computing in main Manipal campus or Bangalore is usually very competitive.

• For main Manipal campus, CSE cutoffs for general category usually go above 170–180.
• In Manipal Bangalore (MIT Bangalore), you might stand a better chance with 136, especially in later counselling rounds.

• Manipal Mangalore campus has relatively lower cutoffs, and they may offer seats in newer specializations depending on demand.

I’d say apply and attend counselling sessions. Even if you don’t get your first choice immediately, there’s a good chance you’ll get something close through spot rounds or if some students drop their seats.

Thank you for reaching out!

A score of 505 in NEET might be competitive for some government medical colleges, but it's not guaranteed. Factors like your category, the state you're applying to, and the specific college you're targeting all play a role. For a general category student, a score of 550+ is often considered a safer bet for securing a government medical seat.

Based on the given information, it is highly unlikely that you will get admission into G. Narayanamma Institute of Technology and Science (GNITS) based solely on your TS Intermediate (IPE) marks.

Here's why:

• TS EAMCET is the primary admission criterion: GNITS primarily admits students to its B.Tech programs based on their rank in the Telangana State Engineering, Agriculture & Medical Common Entrance Test (TS EAMCET).
• No direct admission based on IPE marks: While the eligibility criteria mention that candidates need to have passed the Intermediate examination with a minimum percentage in the prescribed group subjects (MPC), the order of priority for selection is based on:
  1. JEE (Mains) rank
  2. TS EAMCET rank
  3. Marks in the prescribed group subjects in the qualifying examination (IPE). This indicates that your IPE marks are considered only after the EAMCET ranks of all candidates have been evaluated.
• Removal of IPE weightage: For the TS EAMCET 2025 ranking, the 25% weightage previously given to IPE scores has been removed . The rank will be determined solely based on your performance in the TS EAMCET exam.

Therefore, your score of 824 out of 1000 in TS Intermediate will not be the deciding factor for admission. You need to focus entirely on your TS EAMCET preparation and secure a good rank to have a chance of getting a seat in GNITS.

Hope This Helps !

The object distance required to produce a real, magnified image with a convex mirror.

What's given in the problem

Magnification \(M=3\) Radius of curvature (R=30)

Helpful information

Convex mirrors always produce virtual, erect, and diminished images. Therefore, it's impossible to get a real image with a convex mirror. The problem is likely intended for a concave mirror.

Mirror formula: use Magnification formula: Relationship between focal length and radius of curvature: For real images, both \(v\) and \(u\) are negative.

Hope you find it useful

If you are looking for CBSE Class 8 PDF textbooks for the 2025–26 session , including Science, Mathematics, Social Science, Hindi, etc., they can be easily accessed online. The official NCERT website provides free NCERT textbook download option based on the new syllabus. Students and parents can visit the site, choose the class and subject, and download the required PDF files. These digital books follow the updated CBSE curriculum and are useful for regular study, homework, and exam preparation.

Students can download the CBSE class 8th syllabus 2025-26 from the official website of NCERT, at ncert.nic.in. The board follows the NCERT class 8th syllabus , and the core subjects for class 8th are science, maths, English, social science, and Hindi. By downloading the syllabus PDF, the students will be able to know the chapter-wise details and important sections they need to study. The final examination will be conducted for 80 marks, and the internal assessment will be done for 20 marks.

For JEE Mains 2025 preparation, here are some reliable sources where you can download formula books for different subjects:

1. Vedantu : Vedantu provides subject-wise important formula PDFs for JEE Mains, covering Physics, Chemistry, and Mathematics. You can download these PDFs for free.

2. Careers360 : This website offers e-books containing essential formulas for JEE Mains 2025 in Physics, Chemistry, and Mathematics, which can be helpful for your preparation. https://engineering.careers360.com/articles/jee-main-formulas

(You can access this link for JEE formula sheet)

3. SelfStudys : SelfStudys provides subject-wise formula sheets for JEE Mains, which you can download in PDF format.

Hello,

Regarding your query your question is incomplete please elaborate it so we can answer your queries.