All Questions

Chemistry - Class 11

Follow
Showing 11 - 20 out of 34 Questions
393 Views

how many and which questions were repeated in neet 2020?

chandni deb 28th Jun, 2021

Dear Aspirant,

the repeated questions for NEET examinations are generally in most cases low, as the level of competition is very high. In most cases similar kinds of questions are asked instead of repeating the same question. However, there are a few times where a question or two are repeated

241 Views

how to study chemical kinetics for neet?icant solve numericals as they get incorrect...

Anushri Varshney 25th Jun, 2021

Hello dear,

Chemical kinetics is the toughest for some people and also the easiest chapters in Chemistry class 12th. I think some concepts are not clear to you that's why you are lagging in this chapter. Understand the concepts clearly the reactions: first order, second order and third order. Most

211 Views

the process of soap formation is known as

snigdha vig 5th Apr, 2021

Hi,

The process of formation of soap is referred to as saponification.

Basically, it is a  conversion of fat, oil, or lipid , into soap  and alcohol by the action of heat in the presence of aqueous alkali. Soaps are basically salts of fatty acids that have long carbon chains

197 Views

For the reversible reaction N2(g) + 3H2(g) 2NH3(g) at 500C, the value of Kp is 1.44x10-5 Find the value of Kc

shelly 29th Mar, 2021

Dear Student,

Please study from books your NCERT books or you can search your textbook related questions on different platforms like toppr and doubtnet because here I can not teach you and explain you all these.You have to remember the formulas to solve this kind of questions and should know

1076 Views

Derive the equation of ionisation constant and ionic product of water.

Jainshahajal 29th Mar, 2021

Hello Aspirant,

DISSOCIATION CONSTANT AND IONIC PRODUCT OF WATER - DEFINITION

H2OH++OH−

This ionization is known as self-ionization of water.

Dissociation constant=K=[H2O][H+][OH−]

Ionic product of water may be defined as the product of molar concentration of H+ ions and OH− ions.

Kw=[H+][OH−]=10−14

K=55.5510−14=1.8×10−16

IONISATION OF WATER :-

The self-ionization of

5223 Views

Aluminum form [AlF6]3 but boron does not form [BF6]3

Koustav Dey 29th Mar, 2021

Hello,

Aluminium has vacant d-orbitals. So, it can expand its coordination number from 4 to 6. Thus, it forms octahedral [AlF6]3- ion in which Al undergoes sp3d2 hybridisation.

On the other hand, Boron does not have d-orbitals. Therefore, it can have a maximum coordination number of 4. So, boron can

173 Views

12 .Assertion : SiCl4 reacts with water,CCl4 does not. Reason :SiCl4 is ionic whereas CCl4 is covalent. 13. Assertion : Energy of resonance hybrid is equal to the average of energies of all canonical forms. Reason : Reason hybrid cannot be presented by a single structure.

Vibhanshu 28th Mar, 2021

12. Assertion and Reasons are both true and it is the correct explanation.

Si has d-orbitals to accept electrons donated by water but C does not.
Therefore, SiCl4SiCl4 reacts with water but CCl4CCl4 does not.

13. Assertion is not correct but Reason is correct

Resonance hybrids are always more stable

46 Views

how can read jee mains ebooks for careers 360

chinchujoseph1993 4th Mar, 2021

Hello,

I will share with you a link from where you can download JEE Mains related Ebooks available on this platforn:

https://engineering.careers360.com/download/jee-main-ebooks?page=1


Also you can download previous year question papers and sample papers which you can practice during your preparation time. Below I have shared a link where you can

768 Views

Environmental Chemistry Weightage in 2021 jee main.

Shrishty sahu 21st Feb, 2021
Dear student,
The environmental chemistry has a weightage if 2 questions that carry 8 marks out of 300 marks of jee mains paper. This is an important chapter and if you study it nicely then you can easily grab 8 marks which means a lot.
For more info about the
199 Views

3B eqilibrium 3A. K1 2C eqilibrium 2B. K2 C eqilibrium D. K3 K for. D equilibrium A=?

ARYAN SAGAR 13th Feb, 2021

Dear student,

Equilibrium Constant ( k ) = [products]^x / [reactants]^y  { where x and y are stoichiometric coefficients of products and reactants respectively}.

Now, coming onto the question :-

K1 = ([A]/[B])^3

So, [B] = [A]/(K1)^1/3

K2 = ([B]/[C])^2

So, [C] = [B]/(K2)^1/2 = [A]/((k1)^1/3 (k2)^1/2)

Now, K3 =

The question have been saved in answer later, you can access it from your profile anytime. Access now