The number of water molecules is maximum in------
hello rohit
As we know that for a molecule, molecular weight in grams is equal to the Avogadro number and for transforming between moles and grams, we could use the molar mass of the substance. Avogadro’s number can be expressed as the number of elementary particles such as molecules, atoms, compounds, etc. per mole of a substance and Avogadro number is often denoted as NA.
18 mole of water will contain 18×6.023×1023 number of molecules.
therefore the number of water molecules is maximum in 18 moles of water.
hope this will help you a lot.
thank you.
no of molecules in 4.25 gram NH3
hello Sr,
Hope you are doing well ,Now to answer your question
As we know that Molar mass of ammonia is 17g
17g ammonia contains 6.022×10^23 number of ammonia molecules due to this 4.25 g ammonia will contain,
(6.022×10^23×4.25)/17 = 1.5×10^23
number of ammonia molecules.
hope this will help you a lot
thank you.
calculate the number of molecules in 0.49 gram h2 so4 ( s= 32)
hello s r,
As we know that,
Mass of Sulphuric (H2SO4) = 0.49g
We have the number of molecules in 0.49g of H2SO4
Molecular mass of H2SO4 = (Atomic mass of H) x 2 + (Atomic mass of S) x 1 + (Atomic mass of O) x 4
Molecular mass of H2SO4 = ( 1 x 2) + (32 x 1) + (16 x 4)
= 2 + 32 + 64
= 98.
Now,
According to the formula,
Number of moles in the given H2SO4(n)
= Mass of H2SO4 in grams/Molecular mass of H2SO4
= 0.49/98
= 0.01/2
= 0.005
: n = 0.005 mol
: 1 mol of H2SO4 contains 6.022 x 10^23 molecules.
: 0.005 mol of H2SO4 contains 0.005 x 6.022 x 10^23 molecules.
= 0.003011 x 10^23 molecules .
that is 0.49 g of H2SO4 contains 0.003011 x 10^23 molecules of H2SO4.
hope this will help you lot.
molecular orbital theory of homonuclear diatomic molecules
hello candidate,
hope you are doing well, Now coming back to your question as we know that
Homonuclear diatomic molecules contain two atoms of the same element.
Molecular orbitals exhibit the same general properties as atomic orbitals, including a nodal structure.
The Molecular orbital diagram gives the list of molecular orbitals which are filled with the required number of electrons starting from the lowest energy level onward. Hunds maximum multiplicity rule is followed when filling electrons in degenerate levels, so two electrons in two degenerate levels will be unpaired.
hope this will help you a lot,
thank you.
a woman had just undergone if kidney transplant a bioactive molecules drug is administered to a pose filmi rejection by the body what is the bioactive molecules name the microbes from which date is abstract
Hello student, hope you are safe and healthy!
After the woman completed her kidney transplant, the problem of rejection of the transplanted kidney arises. This is because her body will think this new kidney is “foreign” and will try to protect her by “attacking” it. To prevent this rejection, anti-rejection bioactive drugs are administered. These bioactive molecules are called immunosuppressants .
The Anti–rejection (immunosuppressant) medications decrease the body’s natural immune response to a “foreign” substance (your transplanted kidney). They lower (suppress) her immune system and prevent her body from rejecting her new kidney.
The immunosuppressive agent used for preventing rejection of transplanted organs is Cyclosporin-A . It is produced by submerged fermentation of aerobic fungi identified as Trichoderma polysporum .
Hope this answer helps:)
Happy learning!
a certain public water supply contains 0.10 ppb of chloroform .how many molecules of chloroform would be obtained in 0.478 ml drop of this water ?
Hi Garima,
It is given that there is 0.10 ppb of chloroform in a certain water supply, which means 10^9 g of water contains 0.10 g of CHCL3 ( because 1 billion = 10^-9)
Now volume of water = 0.478 mL (given)
Assume density of water to be 1 g/mL
Mass of the water can be calculated as, mass = density * volume
Therefore, mass = 0.478 ml * 1 g/mL = 0.478 g
Now, 10^9 g of water contains 0.10 g of CHCL3
Therefore, 1 g of water will contain 0.10 g / 10^9 g of CHCL3 = 10^-10 g of CHCL3
Therefore, 0.478 g of water will contain 0.478 * (10^-10) g of CHCL3
Now, no. of moles can be calculated using the formula = Given Mass/ Molecular Mass
Therefore no. of moles of CHCL3 = (0.478 * 10^-10) / 119.5 = 0.004 * (10^-10) = 4 * (10^-13)
(molecular mass of CHCL3 = 119.5 g)
Now one mole of any compound contains = Na no. of molecules
therefore 4 * (10^-13) moles of CHCL3 will contain 4* 10^-13 * Na no. of molecules
Therefore, 0.478 mL of this water will contain 4 * 10^-13 * Na molecules of CHCL3
Hope this helps!
Which one will have maximum numbers of water molecules
hello adnan,
As we know that for a molecule, molecular weight in grams is equal to the Avogadro number and for transforming between moles and grams, we could use the molar mass of the substance. Avogadro’s number can be expressed as the number of elementary particles such as molecules, atoms, compounds, etc. per mole of a substance and Avogadro number is often denoted as NA.
18 mole of water will contain 18×6.023×1023 number of molecules.
therefore the number of water molecules is maximum in 18 moles of water.
hope this will help you a lot.
thank you.
If 2 molecules of sucrose have to be respired then the number of atp produced by anaerobic oxidation of glucose
Hello student,
As per we know that the respiration of 1 mole sucrose in UN aerobic oxidation produced 2 adenosine triphosphate.
So 2 molecules of sucrose are used in produced by anaerobic oxidation the total number of atp produced is about 4 nos.
And if it is done by aerobic oxidation the total number can be 128 nos of atp.
Hope this will help you