NIOS
Hello,
Yes, absolutely you can reappear for your class 12th with NIOS with 5 subjects for JEE. JEE doesn't consider if you have repeated or not as long as you meet the eligibility criteria. So, you can appear for class 12th again with NIOS. A lot of students follow this step to become eligible for JEE. So, prepare and work harder and you will definitely achieve success.
Hope this helps you,
Thank you
Yes as per the Information Bulletin by NTA. Senior Secondary School Examination conducted by the National Institute of Open Schooling with a minimum of five subjects. will be eligible to write an exam for JEE Mains. But to sit for JEE Advanced exam, only top 2.5 lakhs students will get eligible who has given the JEE Mains exam. The Qualifying cutoff for JEE Advanced exam will be out, once the result for JEE mains session 2 exam is out. Thanks
Yes as per the information Bulletin the eligibility criteria for Academic Qualification candidate who have passed the Senior Secondary School Examination conducted by the National Institute of Open Schooling with a minimum of five subjects will be eligible to write the exam.
YES, One can become a pilot regardless the stream they are in. You just need pass math's exam from NIOS or any designated open university then only you can join any good flying school. Criteria is only that a candidate must have passed there class 10th and class 12th with physics and math's these are the main two criteria one has to clear to become a pilot.
Question : $\triangle \mathrm{ABC}$ is a right-angle triangle at $\mathrm{B}$. If $\tan \mathrm{A}=\frac{5}{12}$, then $\sin \mathrm{A}+\sin \mathrm{B}+\sin \mathrm{C}$ will be equal to:
Option 1: $1 \frac{5}{13}$
Option 2: $2 \frac{4}{13}$
Option 3: $3 \frac{1}{13}$
Option 4: $2 \frac{1}{13}$
Correct Answer: $2 \frac{4}{13}$
Solution : Given, $\tan\mathrm{A}=\frac{5}{12}$ Using Pythagoras theorem, $AC^2 = AB^2+BC^2$ ⇒ $AC^2 = 5^2 + 12^2$ ⇒ $AC^2 = 25 + 144$ ⇒ $AC^2 = 169$ ⇒ $AC = 13$ units ⇒ $\sin \mathrm{A} = \frac{5}{13},$ $\sin \mathrm{B} = 1$ and $\sin\mathrm{C} = \frac{12}{13}$ So, $\sin \mathrm{A}+\sin \mathrm{B}+\sin \mathrm{C}$ = $\frac{5}{13}+1+\frac{12}{13}$ = $\frac{12+13+5}{13}=\frac{30}{13}=2\frac{4}{13}$ Hence, the correct answer is $2\frac{4}{13}$.
Hello Aspirant
Unfortunately, you are not eligible for a nursing program in Jharkhand with an Arts background.
To pursue a nursing degree, you need to have completed your 10+2 with Physics, Chemistry, and Biology (PCB) from a UGC-recognized Board of Examination. This is a standard requirement for nursing programs across most Indian states, including Jharkhand.
The Jamshedpur College's website might have mentioned accepting NIOS students, this usually refers to students who have completed their 10+2 with the required science subjects through NIOS. Since you are from an arts background, you will not be eligible to apply for Nursing, even if you were an NIOS student.
NIOS is a recognized and valid education board and it is acceptable in higher studies as well as government jobs. Hence, you are eligible for Christ University as the eligibility for admission is that the Candidates must have passed 12th or an equivalent examination(ISC/CBSE/NIOS/IGCSE/KARNATAKA PUC/IB BOARD EXAMINATION) in any stream from any recognized educational board of India.
I hope this helps,
The short to your question is Yes!!, it is definitely possible to get admission in B-Tech through the NIOS board. Many colleges in India accept this board for admission, so you have options to choose from. You should have no hard time having problems to get a College that accept NIOS board.
https://www.careers360.com/courses/b-tech-bachelor-of-technology
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
And never miss an important update