NIOS
Question : Vasco da Gama, a Portuguese explorer came to India in ___.
Option 1: 1496
Option 2: 1498
Option 3: 1495
Option 4: 1497
Correct Answer: 1498
Solution : The correct answer is 1498.
Vasco da Gama, the Portuguese explorer, arrived in India on May 20, 1498. Upon his arrival in Calicut, Vasco da Gama established trade relations with the local rulers and secured valuable spices, such as pepper and cinnamon. His successful
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You can opt to reappear for your board exams to improve your percentage. This is the most straightforward way to ensure you meet the 75% criteria. but it will take more time.
second option is that, If you're considering switching to the NIOS board, this
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Yes, absolutely you can reappear for your class 12th with NIOS with 5 subjects for JEE. JEE doesn't consider if you have repeated or not as long as you meet the eligibility criteria. So, you can appear for class 12th again with NIOS. A lot of students follow this
Yes as per the Information Bulletin by NTA. Senior Secondary School Examination conducted by the National Institute of Open Schooling with a minimum of five subjects. will be eligible to write an exam for JEE Mains. But to sit for JEE Advanced exam, only top 2.5 lakhs students will get
Yes as per the information Bulletin the eligibility criteria for Academic Qualification candidate who have passed the Senior Secondary School Examination conducted by the National Institute of Open Schooling with a minimum of five subjects will be eligible to write the exam.
YES, One can become a pilot regardless the stream they are in. You just need pass math's exam from NIOS or any designated open university then only you can join any good flying school. Criteria is only that a candidate must have passed there class 10th and class 12th
Question : $\triangle \mathrm{ABC}$ is a right-angle triangle at $\mathrm{B}$. If $\tan \mathrm{A}=\frac{5}{12}$, then $\sin \mathrm{A}+\sin \mathrm{B}+\sin \mathrm{C}$ will be equal to:
Option 1: $1 \frac{5}{13}$
Option 2: $2 \frac{4}{13}$
Option 3: $3 \frac{1}{13}$
Option 4: $2 \frac{1}{13}$
Correct Answer: $2 \frac{4}{13}$
Solution : Given, $\tan\mathrm{A}=\frac{5}{12}$ Using Pythagoras theorem, $AC^2 = AB^2+BC^2$ ⇒ $AC^2 = 5^2 + 12^2$ ⇒ $AC^2 = 25 + 144$ ⇒ $AC^2 = 169$ ⇒ $AC = 13$ units ⇒ $\sin \mathrm{A} = \frac{5}{13},$ $\sin \mathrm{B} = 1$ and $\sin\mathrm{C} = \frac{12}{13}$ So, $\sin
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Unfortunately, you are not eligible for a nursing program in Jharkhand with an Arts background.
To pursue a nursing degree, you need to have completed your 10+2 with Physics, Chemistry, and Biology (PCB) from a UGC-recognized Board of Examination. This is a standard requirement for nursing programs across
NIOS is a recognized and valid education board and it is acceptable in higher studies as well as government jobs. Hence, you are eligible for Christ University as the eligibility for admission is that the Candidates must have passed 12th or an equivalent examination(ISC/CBSE/NIOS/IGCSE/KARNATAKA PUC/IB BOARD EXAMINATION) in any
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