We can split the denominator into two Co-prime numbers as 17 and 8.
First we'll find d remainder of 107^1444/17 ~5^1444/17=5^16n*5^4/17~~1*5^4/17
Remainder =13
So 107^1444 is a 17n+13 number
Next find the of 107^1444/8 in d same way
We will get 8n+1 number. This all can be done by using a remainder theorem.
Then the next step is to find a number below 136 that is divisible by both 17n+13 as well as 8n+1 number.
The list of 17n+13 numbers below 136 is:13,30,47,64,81,98,115 n 132.
81 can be seen to be an 8n+1 number too
Thus, the correct answer is 81

Divya How is (5^ 1444)/17 =
(5^16n *5^4)/17