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I am getting 96.8 percentile in jee mains 1st attempt can i get any good Nit or IIIT at this rank?


SINGH 14th Dec, 2019
Answers (2)
Shubham Dhane 23rd Jan, 2020

Hello,

We can use the below formula to predict your rank

100 - your total percentile score is the percentage  of people ahead of you. 869010 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100

Your predict score will be 27808 but this is approximate rank and it may change after april attempt

But with your present rank as you haven't mentioned your category or state its difficult to tell you about which colleges you might get. Please click the below link to use the college predictor to predict what college you might get

B.Tech/B.Arch Admissions OPEN

Apply to Amity University-Noida B.Tech Admissions 2026

https://engineering.careers360.com/jee-main-college-predictor?ici=cp-listing_engineering&icn=JEE-Main-College-Predictor


2 Comments
Comments (2)
23rd Jan, 2020
i am general candidate from jharkhand.
Reply
25th Jan, 2020
SINGH According to 2019 cut off trends you may get seat in NIT, Jamshedpur.A general candidate with rank 32896 secured a seat in civil engineering, a general category category with rank 27859 secured a seat in mechanical engineering and a general category candidate with rank 36919 secured a seat in metallurgy and materials engineering.But the cut off changes every year it may increase or decrease slightly.
Reply
Pooja Kaushik 23rd Jan, 2020
Hi aspiration,
yes you have done exceptionally well and you can get admission still you may calculate your expected rank by this formula

100 - your total percentile score is the percentage  of people ahead of you. 869010 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100

If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100

Hope for the best.
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